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marin [14]
2 years ago
13

(3.5 x 10 ^ -4) ÷ (5 x 10 ^ 5) in standard form

Mathematics
1 answer:
Maslowich2 years ago
8 0

Answer:

0.7 x 10 ^ -9

Step-by-step explanation:

(3.5 x 10 ^ -4) ÷ (5 x 10 ^ 5)

3.5 / 5 x 10 ^ -4/ 10 ^ 5

=> 0.7 x 10 ^ -9

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A bank features a savings account that has an annual percentage rate of 3.5% with interest compounded quarterly. Vanessa deposit
vazorg [7]

Answer:

APY = 0.04 or 4%

Step-by-step explanation:

Given the annual percentage rate of 3.5% that is compounded quarterly, and a principal of $6,500:

We can use the following formula to solve for the annual percentage yield (APY):

APY =  (1 + \frac{r}{n})^n - 1

where <em>r</em> = interest rate = 3.5% or 0.035

<em>           n</em> = number of compounding periods per year = 4

We can plug in the values into the equation:

APY =  (1 + \frac{r}{n})^n - 1

APY =  (1 + \frac{.035}{4})^4 - 1

APY =  (1 + 0.00875)^4 - 1

APY =  (1.00875)^4 - 1

APY = 1.03546 - 1  

APY = 0.04 or 4%        

8 0
2 years ago
Find the Maclaurin polynomials of orders n = 0, 1, 2, 3, and 4, and then find the nth Maclaurin polynomials for the function in
Zielflug [23.3K]

Answer:

Σ(-1)^kx^k for k = 0 to n

Step-by-step explanation:

The nth Maclaurin polynomials for f to be

Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......

The given function is.

f(x) = 1/(1+x)

Differentiate four times with respect to x

f(x) = 1/(1+x)

f'(x) = -1/(1+x)²

f''(x) = 2/(1+x)³

f'''(x) = -6/(1+x)⁴

f''''(x) = 24/(1+x)^5

To calculate with a coefficient of 1

f(0) = 1

f'(0) = -1

f''(0) = 2

f'''(0) = -6

f''''(0) = 24

Findinf Pn(x) for n = 0 to 4.

Po(x) = 1

P1(x) = 1 - x

P2(x) = 1 - x + x²

P3(x) = 1 - x+ x² - x³

P4(x) = 1 - x+ x² - x³+ x⁴

Hence, the nth Maclaurin polynomials is

1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n

= Σ(-1)^kx^k for k = 0 to n

6 0
3 years ago
Divide. −1/9÷3/4 <br> −4/27 <br> −1/12 <br> 1/12 <br> 4/27<br> PLZZZZ HELP FAST!
ivanzaharov [21]

\frac{ - 1}{9}  \div  \frac{3}{4}  \\  \\  \frac{ - 1}{9}  \times  \frac{4}{3}  \\  \\  \frac{( - 1) \times 4}{9 \times 3}  \\  \\  \frac{ - 4}{27}

7 0
3 years ago
Marley runs 5 yards down the track from point A to point B, and then stops and runs
julia-pushkina [17]

Answer:

\sqrt{61}=AC or 7.8102=AC

Step-by-step explanation:

If we connect a line from point A to point C we create a triangle, and we can use pythagorean theorem to find this distance. So the line from point A to point C will be our hypotenuse and the other two distances will be out side lengths.

5^{2}+6^{2}=AC^{2}

25+36=AC^{2}

61=AC^{2}

\sqrt{61}=AC or 7.8102=AC

3 0
3 years ago
1-cos^2 A / sec^2 A - tan^2 A
tiny-mole [99]
I hope this helps you



✔cos^2A+sin^2A=1


✔1-cos^2A=sin^2A

✔cos2A=cos^2A-sin^2A

✔sin2A=2.sinA.cosA


secA=1/cosA


tgA=sinA/cosA


sin^2A/1/cos^2A-sin^2A/cos^2A


sin^2A.cos^2A/cos2A

2.sin^2A.cos^2A/cos2A


sin2A.2.sin2A/cos2A


tg2A.2.sin2A


6 0
2 years ago
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