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NemiM [27]
3 years ago
6

As part of a statistics project, Andrea would like to collect data on household size in her city. To do so, she asks each person

in her statistics class for the size of their household, and reports that her sample is a simple random sample. However, this is not a simple random sample. Which of the following are valid reasons for why this is not a sample that is appropriate for this research question Why?
Charlie did not use any randomization; he took a convenience sample.

Charlie did not use a random number table to randomize the order in which he collected the students' responses, so the sample cannot be random.

In this investigation of household size, each household represents a case. Charlie incorrectly sampled individuals instead of households.
Mathematics
1 answer:
strojnjashka [21]3 years ago
7 0

Answer:

Charlie did not use any randomization; he took a convenience sample.

Step-by-step explanation:

The first question we need ask is whether his classmates make up the population of the city? Or does it mean that his classmate will give unbiased representation of the entire city? Because we are certain there are many other schools within the city of interest. Less assume he can do that, what will happen to all other schools? These are many other factors rendered his choice of sampling inappropriate for this study.

Therefore, the process is not random but convenience sample, even though they might give information about their various household sizes, it might not give the true picture of the city he is trying to investigate.

The best approach should have been a probability sampling techniques, preferably a systematic random sampling approach. If he has followed this process of sample selection, it will give a more reliable and well representative sample to determine the households size in the city of his interest.

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Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
Can someone help me with the problems in the images
dezoksy [38]

Answer:

the first one is 5. 5 and second is 5

Step-by-step explanation:

sorry i couldnt do the others

3 0
3 years ago
Read 2 more answers
A paper company needs to ship paper to a large printing business. The paper will be
slamgirl [31]
45x+75y=1410 i hope this helps bc i’m pretty sure i’m learning the same thing but i hope this helps
3 0
3 years ago
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!!!
Mamont248 [21]

Answer:

y= -x^2+5

Step-by-step explanation:

It normally expontionally goes up, so across the x axis is down so it is negative, and is is all scales up, so the start is 5 up from the origin on the y axis, so it would be y=-x+5

Hope this helped!

7 0
3 years ago
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
3 years ago
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