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maksim [4K]
3 years ago
15

Find the maximum and the minimum value of the following objective​ function, and the value of x and y at which they occur. The f

unction F=2x+16y subject to 5x+3y≤37, 3x+5y≤35, x≥0, y≥0
The maximum value of the objective function is ___ when x=___ and y=___
Mathematics
1 answer:
kumpel [21]3 years ago
8 0

Answer:

The maximum value of the objective function is 112 when x = 0 and y = 7.

Step-by-step explanation:

Given the constraints:

5x+3y≤37, 3x+5y≤35, x≥0, y≥0

Plotting the above constraints using geogebra online graphing tool, we get the solution to the constraints as:

A(0, 7), B(7.4, 0), C(5, 4) and D(0, 0)

The objective function is given as E =2x+16y, therefore:

At point A(0, 7):  E = 2(0) + 16(7) = 112

At point B(7.4, 0): E = 2(7.4) + 16(0) = 14.8

At point C(5, 4): E = 2(5) + 16(4) = 74

At point D(0, 0): E = 2(0) + 16(0) = 0

Therefore the maximum value of the objective function is at A(0, 7).

The maximum value of the objective function is 112 when x = 0 and y = 7.

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How do I use the cosine rule for these problems?
Elenna [48]

Answer:

see explanation

Step-by-step explanation:

Using the Cosine rule

a² = b² + c² - 2abcosA ← Rearranging for cosA gives

cosA = \frac{b^2+c^2-a^2}{2ab}

(a)

let a = 10, b = 7, c = 8 and A = α, then

cosα = \frac{7^2+8^2-10^2}{2(7)(8)} = \frac{49+64-100}{112} = \frac{13}{112}, thus

α = cos^{-1}( \frac{13}{112} ) ≈ 83° ( to the nearest degree )

(b)

let the angle opposite side 7 be x

Using the Sine rule

\frac{10}{sin83} = \frac{7}{sinx} ( cross- multiply )

10sinx = 7sin83 ( divide both sides by 10 )

sinx = \frac{7sin83}{10} , thus

x = sin^{-1} ( \frac{7sin83}{10} ) = 44°

The third angle can be found using the sum of angles in a triangle

third angle = 180° - (83 + 44)° = 180° - 127° = 53°

The 3 angles are 83°, 44°, 53°

6 0
3 years ago
Graph the solutions of the inequality on a number line.
nadya68 [22]
The answer that would be correct is C.
4 0
3 years ago
1. Find the HCF of the following numbers by prime factorisation and continued division method10,35,40​
statuscvo [17]

Answer:

Step-by-step explanation:

10 = 2*5

35 = 5*7

40 = 2*2*2*5

The number 5 is common to all three  factorisations

So the HCF = 5.

Continued division:

10 and 35:

 10) 35(3

       30

          5)10(2

              10

                0

- so the HCF of 10 and 35 is 5.

10 and 40:

10)40( 4

     40

        0  

So the HCF of 10 and 40 is 10

We found HCF of 10 and 35 is 5 so:

HCF of 10, 35 and 40 is HCF of 5 and 10 which is 5.  

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3 years ago
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inysia [295]

Answer:

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Step-by-step explanation:

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5 0
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