Answer:
The correct answer will be- Meiosis I, anaphase I
Explanation:
Alleles are the variant alternative forms of a gene which determines the trait of an organism. The trait or phenotype is expressed only when the two alleles controlling a single trait on separate chromosomes are aligned in a complementary position.
During gamete formation, the alleles controlling a trait segregate independently of each other. This segregation of alleles takes place during Anaphase I of meiosis I. During anaphase, the sister chromatids are separated by the mitotic spindles so that the chromosomes can reach the opposite poles.
Thus, Meiosis I, anaphase I am the correct answer.
The correct answer is G. plants can't grow into each other, so when they are tightly packed together they will not grow as large as they would if they were spaced out.
Answer:
Thanks for you question. Your hypothesis suggests a linear relationship between serum Cholesterol levels and MI. This hypothesis seems to ignore the difference in the prevalence and effectiveness of LDL receptors in the FH patient.
FH patients who have inherited the mutation from both parents have very few LDL receptors in their blood and therefore almost no ability to pass the unused Cholesterol through the liver. FH patients who are heterozygous will have more LDL receptors although both will find Cholesterol removal problematic without the addition of a PCSK9 inhibitor.
In short, your hypothesis need to account for other factors that are in play.
Explanation:
Consider my case. I am a 64 year old male who has Heterozygous Familial Hypercholesterolemia. Before treatment at age 12 my Total cholesterol was 510 mg/dl. My genetic testing shows two mutations to the LDL Receptor gene with only one mutation being pathogenic. My first heart attack was at 47 and first stroke at 62. My current LDL is too low to detect with the use of a PCSK9 inhibitor (Repatha®).
Answer:
The force of spring will be "3.75 N". The further explanation is given below.
Explanation:
The given values are:
Spring constant, K = 75.0 N/m
x₁ = 0.200 m
x₂ = 0.150 m
So that,
⇒ 
⇒ 
⇒ 
Now,
Force of spring will be:
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On putting the estimated values, we get
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