Each colection day: D
Number of tops collected on that day: N
D1=1; N1=2
D2=3; N2=8
1) Linear model
N-N1=m(D-D1)
m=(N2-N1)/(D2-D1)
m=(8-2)/(3-1)
m=(6)/(2)
m=3
N-N1=m(D-D1)
N-2=3(D-1)
N-2=3D-3
N-2+2=3D-3+2
N=3D-1
when D=6:
N=3(6)-1
N=18-1
N=17
<span>What is the number of tops collected on the sixth day based on the linear model?
</span>The number of tops collected on the sixth day based on the linear model is 17.
2) Exponential model
N=a(b)^D
D=D1=1→N=N1=2→2=a(b)^1→2=ab→ab=2 (1)
D=D2=3→N=N2=8→8=a(b)^3→8=a(b)^(1+2)
8=a(b)^1(b)^2→8=ab(b)^2 (2)
Replacing (1) in (2)
(2) 8=2(b)^2
Solving for b:
8/2=2(b)^2/2
4=(b)^2
sqrt(4)=sqrt( b)^2 )
2=b
b=2
Replacing b=2 in (1)
(1) ab=2
a(2)=2
Solving for a:
a(2)/2=2/2
a=1
Then, the exponential model is N=1(2)^D
N=(2)^D
When D=6:
N=(2)^6
N=64
<span>What is the number of tops collected on the sixth day based on the exponential model?
</span><span>The number of tops collected on the sixth day based on the exponential model is 64</span>
Answer:
40% = 0.40
800 / 0.40 = 2000 total tickets were sold
Step-by-step explanation:
For the answer to the question above, this is a right triangle problem using the tangent function.
<span>Tan(x) = Opposite (O) / Adjacent (A) </span>
<span>x = 40 degrees </span>
<span>A = 30 ft </span>
<span>Solve for O </span>
<span>O= Tan (x) * A </span>
<span>O = Tan (40) * 30 </span>
<span>Use your calculator or whatever method to get the tangent of 40 degrees (which is .84) </span>
<span>O = .84 * 30 </span>
<span>O = 25.2 Ft</span>
Answer:
12.25
Step-by-step explanation:
49 divided by 4 = 12.25
Checking answer
12.25 • 4 = 49
