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2 years ago

What Is the slope of a line perpendicular to y=x-6

1 answer:

7 0

The slope of a line that is perpendicular to y = x - 6 means that the slope has to be a negative reciprocal of the original slope

That means the slope of the line that is perpendicular to y = x - 6 is '-1'

Hope that helps!

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Runner a averages 5 mph and run it B rat averages 6 mph these rates how much longer does it take runner A then runner be to run

Kipish [7]

Takes runner A 18 more minutes

8 0

3 years ago

Which polynomial can be simplified to a difference of squares

Mrrafil [7]

<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)$

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

$First=10a^{2}$

$Second=16a^{2}$

$Third=25a^{2}$

$Fourth=24a^{2}$

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

$16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}$

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

$16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)$

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

$25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}$

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}$

7 0

3 years ago

Read 2 more answers

Bob spends 30 hours in 4 weeks of gardening. How many hours does he garden in 5 weeks

Mademuasel [1]

Answer:

37.5 hrs

Step-by-step explanation:

You do cross multiplication hours on top and weeks on the bottom.

4 0

3 years ago

Find the arc length of a 30 degree sector of a circle with a radius of 10 cm

Elena-2011 [213]

Arc length = Ф/360 * 2πr
= 30/360 * 2*3.14*10
= 1/12 * 62.8
= 5.23

In short, Your Answer would be 5.23 cm

Hope this helps!

3 0

3 years ago

The accompanying graph shows the revenue from sales of summer sandals. a) At what price will the company receive the maximum amo

anyanavicka [17]

Hi how are you at this time?

8 0

3 years ago