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3 years ago

4) y=x+4 х Y -2 0 1 2

Mathematics

1 answer:

Irina-Kira [14]3 years ago

7 0

Answer:

I love algebra anyways

The ans is in the picture with the steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

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Helpppp plssssss helpppppppppp

galina1969 [7]

Both are similar, so Yes.

-All the sides of the squares are equal

-The triangles are also the same, just one is smaller. The one on the right is 2/3 of the one on the left.

8 0

3 years ago

Given the figure below with mBFA = 166° and mBD = 88°, what is Help

Strike441 [17]

Answer:

it should still be 166

Step-by-step explanation:

because bfa should be the same as bda

that's what i learnt about this

but i did this a long time ago so im about 70 percent sure that this is correct

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2 years ago

Michael and Daniel are on a team together. Michael scores 5 points on his turn, but Daniel loses 5 points on his turn.

Tomtit [17]

Answer: They don’t score any points, because since micheal scored 5 points, but Daniel lost those 5 points. They still have 0

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

6 0

3 years ago

Solve the equation. –3x + 1 + 10x = x + 4 x = 1/2 x = 5/6 x = 12 x = 18

elena-s [515]

The correct answer is x=1/2

5 0

3 years ago

Read 2 more answers