)) Greg has $50,000 in a savings account that earns 5% interest per year. The interest is

John has four more nickels than dimes in his pocket, for a total of $1.25. Which equation could be used to determine the numbet

ahrayia [7]

So, you have to have your equation in terms of dimes. What you said about what he has: four more nickels than dimes in his pocket. Will help with our equation.
We know what a nickel and dime is worth. A nickel is .05 and a dime is .1
We don't know how many dimes are in his pocket, since we're trying to solve it.
.1x+(4+x).05=1.25;
In the parenthesis, it shows how there are four more nickels. Let's solve it now.
.1x + (4+x).05=1.25
.1x + .2+ .05x = 1.25; Let's add like terms.
.15x + .2 = 1.25; Subtract .2 from both sides.
.15x= 1.05
1.05÷.15= 7 =x
There are 7 dimes in his pocket, let's check our answer.
We now know there are 11 nickels, since there are four more nickels than dimes.
11(.05) +.1(7) = 1.25
.55+ .7 = 1.25
Now that we've tried it, we know there are 7 dimes in his pocket.
Tell me if this helps!

7 0

4 years ago

A company produces alarm clocks. During the regular workweek, the labor cost for producing one clock is $4.00

Dmitrij [34]

Answer:

The question is not complete, nut here is the complete question ; A company produces alarm clocks. During the regular workweek, the labor cost for producing one clock is $4.00. However, if a clock is produced on overtime, the labor cost is $5.00. Management has decided to spend no more than a total of $51,000 per week for labor. The company must produce 12,000 clocks this week. What is the minimum number of clocks that must be produced during the regular workweek?

Step-by-step explanation:

Tthe detailed analysis and step by step calculation is as shown in the attached file.

6 0

4 years ago

The ratio of the numerator to the denominator of a fraction is 2 to 3. If both the numerator and the denominator are increased b

masha68 [24]

Answer:

The fraction is $\frac{4}{6}$

Option (B) is correct.

$3n-2d=0$ and $4n+8=3d+6$

Step-by-step explanation:

Let n denotes numerator and d denotes denominator of the fraction.

Given : The ratio of the numerator to the denominator of a fraction is 2 to 3.

That is $\frac{n}{d}=\frac{2}{3}$

Cross multiply , we get,

$3n=2d$

Or, $3n-2d=0$ ........(1)

Also, given : . If both the numerator and the denominator are increased by 2, the fraction becomes 3/4

That is $\frac{n+2}{d+2}=\frac{3}{4}$

Cross multiply , We get,

$4{n+2}={3}{d+2}$

$4n+8=3d+6$ .........(2)

$3d-4n=2$ .......(3)

Thus, from (1) and (2) , option (B) follows.

Solving equation (1) and (3) to get the original fraction using elimination method,

3n - 2d = 0 ............(1)

and 3d - 4n = 2 .........(3)

Multiply equation (1) by 3 , we get ,

9n - 6d = 0 ..........(4)

Multiply equation (3) by 2 , we get ,

-8n + 6d = 4 ..........(5)

Adding (4) and (5) , we get,

9n - 6d -8n + 6d = 4 + 0

⇒ n = 4

Put n = 4 in (1), we get

3n - 2d = 0 ⇒ 3(4) - 2d = 0 ⇒ 12 -2d = 0 ⇒ 12 = 2d ⇒ d = 6

so, the numerator is 4 and the denominator is 6.

Thus, the fraction is $\frac{4}{6}$

6 0

3 years ago

Anyone know this question?<br><br>Just B please

Gre4nikov [31]

Answer:

52% and 7

Step-by-step explanation:

There are 25 squares of which 13 are shaded , then

$\frac{13}{25}$ × 100% = 13 × 4% = 52°

(b)

1 square represents $\frac{1}{25}$ × 100% = 1 × 4% = 4%

Then 80% = 80% ÷ 4% = 20

That is for 80% , 20 squares require to be shaded

That is 7 more than the 13 already shaded

4 0

3 years ago

A school has a goal of getting at least 2000 boxtops. They have 872 so far. They have 8 days left to get it. At least how many d

True [87]

Answer:

School needs to collect at least 144 box tops each day to meet their goal.

Step-by-step explanation:

The total requirement of box tops = 2,000

The number of box tops they have already received = 872

So, the box tops left = Total number required- Number of tops received

=2,000 - 872

= 1,128 box tops are left so far.

Number of days left = 8

So, number of minimum tops needed each day = $\frac{\textrm{Total tops required}}{\textrm{Number of days left}}$

= $\frac{1128}{8} = 141$

Hence, they need to collect at least 144 box tops each day to meet their goal.

5 0

3 years ago