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dezoksy [38]
3 years ago
8

Pls explain step by step and pls yell by are adding dividing multiplying etc

Mathematics
1 answer:
ikadub [295]3 years ago
5 0

Answer:

Can you show the whole question

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What is - 0.64? square root
tankabanditka [31]
They square root of 0.64 is 0.8
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If 21,986 people in a city received the influenza vaccine, and a study shows that the vaccine is 74.5% effective, how many peopl
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A triangle has sides that measure 7 units, 6 units, and 9.22 units. What is the area of a circle with a circumference that equal
BabaBlast [244]

Answer:

39 units²

Step-by-step explanation:

the perimeter of triangle =

7+6+9.22 = 22.22 cm

=> the radius oh the circle =

r = c/2π = 22.22/ 2×3.14

= 3.54

so, the area of the circle = π.r²

= 3.14 ×(3.54)²

= 3.14 × 12.53

= 39.34 => 39 units²

5 0
3 years ago
Find the radius and height of a cylindrical soda can with a volume of 256cm^3 that minimize the surface area.
Shtirlitz [24]

Answer:

A) Radius: 3.44 cm.

Height: 6.88 cm.

B) Radius: 2.73 cm.

Height: 10.92 cm.

Step-by-step explanation:

We have to solve a optimization problem with constraints. The surface area has to be minimized, restrained to a fixed volumen.

a) We can express the volume of the soda can as:

V=\pi r^2h=256

This is the constraint.

The function we want to minimize is the surface, and it can be expressed as:

S=2\pi rh+2\pi r^2

To solve this, we can express h in function of r:

V=\pi r^2h=256\\\\h=\frac{256}{\pi r^2}

And replace it in the surface equation

S=2\pi rh+2\pi r^2=2\pi r(\frac{256}{\pi r^2})+2\pi r^2=\frac{512}{r} +2\pi r^2

To optimize the function, we derive and equal to zero

\frac{dS}{dr}=512*(-1)*r^{-2}+4\pi r=0\\\\\frac{-512}{r^2}+4\pi r=0\\\\r^3=\frac{512}{4\pi} \\\\r=\sqrt[3]{\frac{512}{4\pi} } =\sqrt[3]{40.74 }=3.44

The radius that minimizes the surface is r=3.44 cm.

The height is then

h=\frac{256}{\pi r^2}=\frac{256}{\pi (3.44)^2}=6.88

The height that minimizes the surface is h=6.88 cm.

b) The new equation for the real surface is:

S=2\pi rh+2*(2\pi r^2)=2\pi rh+4\pi r^2

We derive and equal to zero

\frac{dS}{dr}=512*(-1)*r^{-2}+8\pi r=0\\\\\frac{-512}{r^2}+8\pi r=0\\\\r^3=\frac{512}{8\pi} \\\\r=\sqrt[3]{\frac{512}{8\pi}}=\sqrt[3]{20.37}=2.73

The radius that minimizes the real surface is r=2.73 cm.

The height is then

h=\frac{256}{\pi r^2}=\frac{256}{\pi (2.73)^2}=10.92

The height that minimizes the real surface is h=10.92 cm.

7 0
4 years ago
Find an expression which represents the sum of (10x-10y) and (−4x+6y) in simplest terms
Evgesh-ka [11]

Answer:

but

i girl

Step-by-step explanation:

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3 years ago
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