Answer:
for the first question, it's (2,2) and for the last question it's (0,2)
Answer:
x = -2, y = 3
Step-by-step explanation:
Given equations are,
4x + 5y = 7 ---------(1)
3x - 2y = -12 ----------(2)
Multiply equation (1) by 3
12x + 15y = 21 ------(3)
Multiply equation (2) by (-4)
-12x + 8y = 48 --------(4)
Now add equations (3) and (4),
(12x + 15y) + (-12x + 8y) = 21 + 48
(12x - 12x) + (15y + 8y) = 69
23y = 69
y = 3
From equation (2),
3x - 2(3) = -12
3x - 6 = -12
3x = 6 - 12
x = -2
Therefore, x = -2 and y = 3 will be the answer.
the quotient of 43 divided by 3 =14.3333.
Answer: 
Step-by-step explanation:
The area of a rectangle can be calculated with the formula:

l: the length of the rectangle.
w: the width of the rectangle.
The area of the remaning wall after the mural has been painted, will be the difference of the area of the wall and the area of the mural.
Knowing that the dimensions of the wall are
by
, its area is:

As they are planning that the dimensions of the mural be
by
, its area is:

Then the area of the remaining wall after the mural has been painted is:
