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Ilia_Sergeevich [38]
3 years ago
10

The force of gravity on the Moon is different from the force of gravity on Earth. This means that an object has different weight

on the Moon than it does on the Earth. By what percent does an astronaut's weight decrease on the Moon?
Astronaut Weight (lb)
On Earth Weight- 183
On the Moon Weight- 25.5

PLEASE HELP!!!
Mathematics
1 answer:
kupik [55]3 years ago
8 0
The astronauts weight decreased by 13.9% :)
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Please help me!!!!!!!!!!!!!!
arsen [322]

Ans

184 sq meter

Step-by-step explanation:

Area of the cuboid box = (2*FA)+(2*SA)+(2*TA)

Where FA= Front face area

SA= Side face area

TA= top face are

Here FA= length * breadth = 10*6=60 sq meter

SA= 10*2= 20 sq meter

TA= 6*2= 12 sq meter

So area of box= 2*60+2*20+2*12= 184 sq meter

7 0
3 years ago
I need help solving this problem
BARSIC [14]
You add the base and to sides which will equal 10 5/12
8 0
3 years ago
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Carol has only 20p and 10p coins in her purse she has three times as many 20p coins and 10p coins if Carol has ?4.20 altogether,
irinina [24]

Suppose that Carol has x 10p coins in her purse. Since she has three times as many 20p coins as 10p coins, then she has 3x 20p coins in her purse.

x coins of 10p value $0.10x and 3x coins of 20p value $0.60x.

In total this amount of money is $(0.10x+0.60x)=$0.70x that is exactly $4.20. Thus, you get the equation

0.70x=4.20.

Solve it:

x=\dfrac{4.20}{0.70}=6.

Carol has 6 coins of 10p and 3·6=18 coins of 20p.


7 0
3 years ago
Read 2 more answers
"Lashonda swam 4 kilometers against the current in the same amount of time it took her to swim 16 kilometers with the current. T
Naddika [18.5K]

Answer:

5 km/h

Step-by-step explanation:

In this problem, Lashonda swam 4 km against the current. So the distance covered in this case is

d_1=4 km

Calling v the velocity of Lahonda without the current, and c the velocity of the current, in this situation Lahonda's velocity is

v-c

So we can write:

t_1=\frac{d_1}{v-c}

where t_1 is the time taken to cover the distance.

When Lashonda swims with the current, her velocity is

v+c

So we can write

t_2=\frac{d_2}{v+c}

where

d_2=16 km is the distance covered in this case, and t_2 the time taken.

The velocity of the current is

c=3 km/h

Since Lashonad takes the same time to cover the two distances,

t_1=t_2

So we can write

\frac{d_1}{v-c}=\frac{d_2}{v+c}

And solving for v, we find Lashonda's velocity without the current:

d_1(v+c)=d_2(v-c)\\d_1 v+d_1c = d_2v-d_2c\\v(d_2-d_1)=c(d_1+d_2)\\v=\frac{d_2+d_2}{d_2-d_1}c=\frac{16+4}{16-4}(3)=5 km/h

7 0
4 years ago
(a)/(5h+q)=t Find a (a)/ means fraction
Elena L [17]

Answer:

Step-by-step explanation:

a/(5h+q) = t

multiply both sides by 5h + q

a / (5h + q) * (5h+q) = t * (5h + q)

a =  t * (5h + q)

I would say this is your answer.

You could distribute the t

a = 5ht + tq

which could also be an answer.

7 0
3 years ago
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