Question

2

Answer 1

Answer:

D.   -$\sqrt{17}$/8

Step-by-step explanation:

Draw a right triangle such that cos (theta) = 8/9.  That means the hypotenuse = 9 and the adjacent side to theta = 8

Use the Pythagorean theorem to find the opposite side to theta

$\sqrt{9^{2} - 8^{2} } = \sqrt{81 - 64} = \sqrt{17}$

tan (theta) = $\sqrt{17}$/8

Since theta is in quadrant IV, the tan is negative.  So, tan (theta) = -$\sqrt{17}$/8