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ehidna [41]
3 years ago
11

Choose the function with the largest constant of variation? A 2-column table with 5 rows. Column 1 is labeled x with entries 1,

2, 3, 4, 5. Column 2 is labeled y with entries 2, 4, 6, 8, 10. A 2-column table with 5 rows. Column 1 is labeled x with entries 2, 4, 8, 12, 16. Column 2 is labeled y with entries 0.5, 1, 2, 3, 4. On a coordinate plane, a line goes through points (0, 0) and (1, 3). On a coordinate plane, a line goes through points (0, 0) and (2, 2).
Mathematics
2 answers:
Leona [35]3 years ago
4 0

A reasonable way to use them is to code the five most-common strings in the ... bytes, compared to a bitmap size of only 6 × 8 bits = 6 bytes. ... Columns 2, 4, 5, and 7 yield the six runs 0,5,1,1,1,eol each. ... 2.3: Replacing 10 by 3 we get x = k log2 3 ≈ 1.58k. ... Table Ans.3: Probabilities and Entropies of Two Symbols.

Zielflug [23.3K]3 years ago
3 0

Answer:

A reasonable way to use them is to code the five most-common strings in the ... bytes, compared to a bitmap size of only 6 × 8 bits = 6 bytes. ... Columns 2, 4, 5, and 7 yield the six runs 0,5,1,1,1,eol each. ... 2.3: Replacing 10 by 3 we get x = k log2 3 ≈ 1.58k. ... Table Ans.3: Probabilities and Entropies of Two Symbols.

Step-by-step explanation:

?

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Answer:

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Step-by-step explanation:

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2 years ago
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Ostrovityanka [42]

Answer:

There are two pairs of solutions: (2,7) and (-1,4)

Step-by-step explanation:

We will use substitution.

y = x^2 + 3

y = x +5

Since the second equation is equal to y, replace y in the first equation with the second equation.

y = x^2 + 3

x + 5 = x^2 + 3

Rearrange so that one side is equal to 0.

5 - 3 = x^2 - x

2 = x^2 - x

0 = x^2 - x - 2

You may use quadratic formula or any form of factoring to find the zeros (x values that make the equation equal to 0).

a = 1, b = -1, c = -2

Zeros = \frac{-b + \sqrt{b^{2}-4ac }  }{2a} and \frac{-b - \sqrt{b^{2}-4ac }  }{2a}

Zeros = 2 and -1

Now that you have your x values, plug them into the equations to find their corresponding y values.

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y = (2)^2 + 3

y = 7

Pair #1: (2,7)

y = x^2 + 3

y = (-1)^2 + 3

y = 4

Pair #2: (-1,4)

Therefore, there are two pairs of solutions: (2,7) and (-1,4).

8 0
2 years ago
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Vinvika [58]
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Step-by-step explanation:

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