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3 years ago

11

A) equal lines B) parallel lines C) perpendicular lines D) None of the above

1 answer:

Sladkaya [172]3 years ago

4 0

Answer:

Equal lines or A

Step-by-step explanation:

Top Equation

- 2x + 2y = 5 Add 2x to both sides

-2x + 2x + 2y = 5 + 2x

2y = 5 + 2x Switch the 2x and 5

2y = 2x + 5 Divide by 2

2y/2 = 2x/2 + 5/2

y = x + 2.5

Bottom equation

Use the same procedure as above to get

y = x + 2.5

Conclusion

Equal or the same line. The only other answer you could give would be none of the above, because the lines are not parallel and they are not perpendicular. I maintain that A is correct if equal means the same line. You must have notes for this. What do they say?

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4 years ago

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

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Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

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3 years ago

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Snezhnost [94]

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3 years ago

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