Answer:
99.89% of students scored below 95 points.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 76.4, \sigma = 6.1](https://tex.z-dn.net/?f=%5Cmu%20%3D%2076.4%2C%20%5Csigma%20%3D%206.1)
What percent of students scored below 95 points?
This is the pvalue of Z when X = 95. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{95 - 76.4}{6.1}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B95%20-%2076.4%7D%7B6.1%7D)
![Z = 3.05](https://tex.z-dn.net/?f=Z%20%3D%203.05)
has a pvalue of 0.9989.
99.89% of students scored below 95 points.
Answer:
![5xy*3xy=15x^2y^2](https://tex.z-dn.net/?f=5xy%2A3xy%3D15x%5E2y%5E2)
Step-by-step explanation:
Multiply 5*3 to get 15, and each x and y is squared, so 5xy needs another set of x and y to have two xs and ys in the final expression, so you multiply
by
to get your answer.
If I helped, I would love a brainliest!
Answer:
2 and 1/2
Step-by-step explanation:
:)
-x^3 -3x^2 -4x
Take out a GCF of -x
-x(x^2 + 3x + 4)
The last option is correct