Answer:
Start
Input n, 2
Calculate if (n%2==0) then is divisible else not divisible
Output number is divisible or not
Stop
Explanation:
A large company such as a retail store or airline reservation system uses a multi-user computer that acts as the central computer in a network.
<h3>
Multi-user computer</h3>
A multi-user operating system (OS) is a computer system that allows multiple users from different computers to have access to a single system's OS resources at the same time.
A mainframe is a multi-user computer capable of connecting hundreds or thousands of users simultaneously. This are used by large companies.
Find out more on Multi-user computer at: brainly.com/question/24540334
Answer: The standard web component layouts and templates makes the web page seem like many others but could also make it easier for users to interact and use the web page without much trouble. The approaches do limit creativity and originality in web page design but its better to have an easy to use web page that can still look good rather than something that is confusing for the users.
Explanation:
Answer:
C. The main method proceeds to the next statement following the t3.join(); statement
Explanation:
join() method allows the thread to wait for another thread and completes its execution. If the thread object is executing, then t3.join() will make that t is terminated before the program executes the instruction. Thread provides the method which allows one thread to another complete its execution. If t is a thread object then t.join() will make that t is terminated before the next instruction. There are three overloaded functions.
join()
join(long mills)
join(long millis, int Nanos)
If multiple threads call the join() methods, then overloading allows the programmer to specify the period. Join is dependent on the OS and will wait .
Answer:
See explaination
Explanation:
public class QuickRich {
static void getRichQuick() {
double amount = 1;
int day = 1;
System.out.println("Day 1: $1");
while (amount < 1000000) {
day++;
if(amount + 1 + (amount/2) < 1000000)
System.out.printf("Day %d: $%.2f + ($1 + %.2f) = $%.2f\n", day, amount, amount/2, amount+(amount/2)+1);
else
System.out.printf("Day %d: $%.2f + ($1 + %.2f) >= $1000000\n", day, amount, amount/2);
amount += (1 + (amount/2));
}
}
public static void main(String[] args) {
getRichQuick();
}
}
