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Sphinxa [80]
3 years ago
12

Can someone please help me?

Mathematics
1 answer:
Ivanshal [37]3 years ago
4 0

Answer:

A

\frac{3+5i\sqrt{3} }{2} or \frac{3-5i\sqrt{3} }{2} (i cant do the 'plus or minus' sign on my laptop, but the answer is A )

Step-by-step explanation:

f(x)=x²-3x+21

(let f(x)=0)

x²-3x+21=0

Use the quadratic formula

\frac{-b + \sqrt{b^{2}-4ac } }{2a} or \frac{-b - \sqrt{b^{2}-4ac } }{2a}

\frac{-(-3) + \sqrt{(-3)^{2}-4(1)(21) } }{2(1)} or \frac{-(-3) - \sqrt{(-3)^{2}-4(1)(21) } }{2(1)}

\frac{3+\sqrt{-75} }{2} or \frac{3-\sqrt{-75} }{2}

\frac{3+5i\sqrt{3} }{2} or \frac{3-5i\sqrt{3} }{2}

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Answer:

1. x = 15, y = 8

2. m∠MSN = 90°

3. x = 20

4. y = 9

5. x = 8, m∠PQS = 24, m∠SQR = 66

6. y = 15, m∠RPT = 55, m∠TPW = 35

Step-by-step explanation:

1. to solve for y

9y + 18 = 90

9y + 18 - 18 = 90 - 18

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9y/9 = 72/9

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to solve for x

5x + x = 90

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2. m∠MSN = 90°, because ∠MSN is a right angle, which is equal to 90

3. To find x

3x + 10 + x = 90

3x + x = 4x

4x + 10 = 90

4x + 10 - 10 = 90 - 10

4x = 80

4x/4 = 80/4

x = 20

4. To find y

7y - 3 + 3y + 3 = 90

7y + 3y = 10

-3 + 3 = 0

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5. To find x

3x + 8x + 2 = 90

3x + 8x = 11x

11x + 2 = 90

11x + 2 - 2 = 90 -2

11x = 88

11x/11 = 88/11

x = 8

To find ∠PQS

∠PQS = 3x

x = 8

so 3(x) = 3(8)

3(8) = 24

so ∠PQS = 24

To find ∠SQR

∠SQR = 8x + 2

x = 8

so ∠SQR = 8(x) + 2 = 8(8) + 2

8(8) + 2

= 64 + 2

= 66

6. To find y

4y - 5 + 2y + 5 = 90

4y + 2y = 6y

-5 + 5 = 0

6y = 90

6y/6 = 90/6

y = 15

To find ∠RPT

∠RPT = 4y - 5

y = 15

so ∠RPT = 4y - 5 = 4(15) - 5

4(15) - 5

= 60 - 5

= 55

To find ∠TPW

∠TPW = 2y + 5

y = 15

so ∠TPW = 2y + 5 = 2(15) + 5

2(15) + 5

= 30 + 5

= 35

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