Since 6 is positive, it's (x+blank)^2
6/2=3, and (x+3)^2 = x^2+6x+9. We have x^2+6x-2, so we have to add 9 to both sides to get (x+3)^2-2=9, then subtract 9 from both sides to get
(x+3)^2-11=0, or (x+3)^2=11. Square root both sides to get x+3=sqrt(11), and x=sqrt(11)-3, which is approximately 0.32
Answer:
k= 13*3-2
k= 39-2
k=37 is the required answer
Answer:
3.33 and 1/3
Step-by-step explanation:
"Dense" here means that there are infinite irrational numbers between two rational numbers. Also, there are infinite rational numbers between two rational numbers. That's the meaning of dense. Actually, that can be apply to all real numbers, there always is gonna be a number between other two.
But, to demonstrate that irrationals are dense, we have to based on an interval with rational limits, because the theorem about dense sets is about rationals, and the dense irrational set is a deduction from it. That's why the best option is 2, because that's an interval with rational limits.
Answer:
Step-by-step explanation:
The better buy is the one where you get more area of pizza per dollar (area/price).
Since the problem gives diameter, we assume the pizzas are circle-shaped.
Circle Area = pi x (radius)², and radius r = 1/2 of diameter d.
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Pizza 1: d = 8 and price is $10
r = 1/2 x d = 4
Area of Pizza 1 = πr² = π(4)² = 16π
*** area/price for Pizza 1 = 16π/$10 = 1.6π area per dollar
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Pizza 2: d = 14 and price is $16
r = 1/2 x d = 7
Area of Pizza 2 = πr² = π(7)² = 49π
*** area/price for Pizza 2 = 49π/16 = 3.0625π area per dollar
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Pizza 2 is the better buy, with more pizza per dollar.
