What is the slope of the function, represented by the table of values below?

1 answer:

8 0

Notice the table of values, thus let's pick two points from it, to check what the slope may be,

$\bf \begin{array}{l|ccccccc}
x&-2&\underline{1}&2&\underline{4}&7\\
y&16&\underline{4}&0&\underline{-8}&-20
\end{array}\\\\
-------------------------------$

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ 1}} &,&{{ 4}}~) 
% (c,d)
&&(~{{ 4}} &,&{{ -8}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{-8-4}{4-1}\implies \cfrac{-12}{3}\\\\\\ \cfrac{-4}{1}\implies -4$

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erik [133]

Answer:

The triangle angle rule says that all of the angles in a triangle will add up to equal 180. So to find x we subtract the given angles ( 45 and 60 in this case) from 180.

x = 180-60-45

180-60-45=75

so x = 75

To find y we know that angle x and and y are angles formed on a straight line that are split up by a triangle segment. These angles are called supplementary angles which add up to equal 180.

So knowing that angle x = 75 we can find angle y by subtracting 75 from 180

180-75=105 so y = 105

Another way we could solve for y is the exterior triangle rule

This rule states that an exterior angle of a triangle is equal to the two opposite interior angles

so y = 45 + 65

45 + 65=105

so y = 105

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (4, 1) and

jenyasd209 [6]

Equation of a line is $x+3y =-3$ .

<h3>What is a perpendicular bisector of the line segment?</h3>

A perpendicular bisector is a line that cuts a line segment connecting two points exactly in half at a 90 degree angle. To find the perpendicular bisector of two points, all you need to do is find their midpoint and negative reciprocal, and plug these answers into the equation for a line in slope-intercept form.

Given that,

Endpoints of the line segment are ( $x_{1},y_{1}$ ) = (4, 1) and ( $x_{2},y_{2}$ ) = (2, -5).