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dalvyx [7]
3 years ago
7

Which of the following equations is written in standard form?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0
Standard Form is ax + by = c, where a, b, and c are not fractions and a is not negative.

So, you can go through each of your options to see which ones work with those rules. 

A. 2.5x + 3y = 12   No, this is not in Standard Form. 2.5 can be rewritten as 2<span>\frac{1}{2}, menaing A is a fraction, which you can't have.

B. -10x - 3y = 1   No, this is not in Standard Form. A is -10, but A can't be negative.

C. 2x + 3y = 12   Yes, this is in Standard Form. It follows all of the rules.

D. 5x + 5y = 10   Yes, this is in Standard Form. It follows all of the rules.

So, C and D are both written in Standard Form.


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Please answer my question<br>100+10% = ​
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110

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10% of 100 is 10

100+10=110

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2. Find the common difference and the recursive formula. a. 22, 19, 16, 13, …
Musya8 [376]

Answer:

The common difference d is d = -3

The recursive formula is: \mathbf{a_n=a_{n-1}-3}

Step-by-step explanation:

We need to find the common difference and the recursive formula.

a. 22, 19, 16, 13, …

First we will find common difference

The formula of arithmetic sequence is: a_n=a_1+(n-1)d

where a_n is nth term, a_1 is 1st term and d is the difference

Looking at the sequence we get: a_1=22, a_2=19

Using these values we can find d, the common difference

a_n=a_1+(n-1)d\\put\:n=2, a_2=19, a_1=22\\19=22+(2-1)d\\19=22+d\\d=19-22\\d=-3

So, the common difference d is d = -3

Now, we will find the recursive formula:

The recursive formula is of type: a_n=a_{n-1}+d

We have found common difference d = -3

So, the recursive formula will be:

a_n=a_{n-1}+d\\a_n=a_{n-1}+(-3)\\a_n=a_{n-1}-3

The recursive formula is: \mathbf{a_n=a_{n-1}-3}

6 0
3 years ago
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