1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zloy xaker [14]
3 years ago
14

Name a pair of complementary angles.PLSS HELP

Mathematics
2 answers:
Reptile [31]3 years ago
5 0

It's A I'm 100% suee

Levart [38]3 years ago
4 0

Answer:

The pair of complementary angles is A (BEA and CEB)

Step-by-step explanation:

Complementary angles are two angles beside each other that add up to 90 degrees. Basically, a 90 degree angle is split in 2.

You might be interested in
Factorise 9 X square + Y square + Z square - 6 X Y + 2 Y Z - 6 x z hence find its value when X is equals to 1 by equal to 2 and
Assoli18 [71]

a) Factor 9x² + y² + z² - 6xy + 2yz - 6xz

This looks a lot like

(x+y+z)² = x² + y² + z²+ 2xy + 2yz + 2xz

except instead of x there's (-3x).   So this must be

(-3x+y+z)² = (-3x)² + y² + z² + 2((-3x)y + (-3x)z + yz)

= 9x² + y² + z² - 6xy + 2yz - 6xz

Looks good.

Answer: (-3x+y+z)²

Since it's a square we could also negate the inside and write this (3x-y-z)²

b) I'll guess that says we want to evaluate this when x=1, y=2, z= -1

(-3(1) + 2 -1)² = (-2)² = 4

Answer: 4

8 0
4 years ago
In the diagram of TRIANGLE ABC show below
vekshin1

Answer:

IM PRETTY SURE ITS 44

Step-by-step explanation:

I HOPE IM RIGHT

4 0
3 years ago
Show your work please . NO LINKS.​
nika2105 [10]

Answer:

i x = 0

ii x = 5,9

iii y = 12

iv y = 0

Step-by-step explanation:

0 = 12x²/(x - 5)(x - 9)

0 = 12x²

0 = x²

x = 0

ii vertical asymptotes at x = 5, 9

asymptotes occur as either term (x - 5)(x - 9) approaches zero

iii horizontal asymptote y = 12

function essentially becomes 12(∞²)/∞² = 12(1) as x goes to ±∞

iv y = 0 where x = 0

6 0
3 years ago
15 people received an email and sent it to 3 different friends each, who in turn each sent it to 2 new people. What percent of t
pashok25 [27]

The original 15 people are 10% of the total number of people who received the mail.

Step-by-step explanation:

Given,

Number of people who received mail = 15

Mail further sent to 3 more friends;

Number of people who received mail from 15 people = 15*3 = 45 people

Number of people who received mail from 45 people = 45*2 = 90 people

Total number of people = 15+45+90 = 150 people

Now,

Percent of original people = \frac{Number\ of\ original\ people}{Total\ number\ of\ people}*100

Percent of original people = \frac{15}{150}*100=10\%

The original 15 people are 10% of the total number of people who received the mail.

Keywords: multiplication, percentage

Learn more about percentages at:

  • brainly.com/question/11018983
  • brainly.com/question/11145277

#LearnwithBrainly

8 0
4 years ago
Jane's basic insurance cost is $559.90 per year. Her insurance company offers a typical "safe-driver discount." What would be he
Travka [436]

559.90 - (559.9 \times 0.10) = 503.91

7 0
4 years ago
Other questions:
  • Inequalities involving absolute value, if you know how to solve it, please help!
    12·1 answer
  • (5,3) and (5,-9) what’s the slope?
    6·1 answer
  • PLEASE HELP ME!!!!!!!!!! 25 POINTS!!!!!!!!!!
    14·2 answers
  • 14+4i+25-10i+26+8i combining complex numbers
    12·1 answer
  • There are 4 dogs at each corner. They each see three dogs. How many dogs are there?
    8·1 answer
  • Four lines are shown in the graph below.<br> Which line has the slope with greatest value?
    13·2 answers
  • The price of a car increased by 7% which expression can be used to calculate the new price of the car
    6·1 answer
  • Can someone help me with this <br> please and thank you<br> have a great day/ night or evening
    7·1 answer
  • A line has a slope of 8 and includes the points (7,y) and (5,-7) no link plz
    8·1 answer
  • !!!!!!PLEASE I NEED HELP!!!!!! I WILL GIVE YOU BRAINLIEST!!!!!
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!