A points location will change after you add a negative value to the y coordinate even if you leave the x coordinate the name because you are changing the value of the y coordinate. For example, if you have (4,6) as a coordinate and then change it to (4,-6), the coordinate will now just be on the other side of the x axis
Step-by-step explanation:
The answer is OPTION C
Find the Inverse of a 3x3 Matrix.
First
Find the Determinant of A(The coefficients of e
Proceed towards finding the CO FACTOR of the 3x3 Matrix.
+. - +
A= [ 1 -1 -1 ]
[ -1 2 3 ]
[ 1 1 4 ]
The determinant of this is 1.
Find the co factor
| 2 3 | |-1 3 | |-1 2 |
| 1. 4. | |1 4 | |1. 1 |
|-1. -1 | |1 -1 | |1 -1
| 1. 4 | |1. 4| |1 1|
|-1. -1 | |1 -1 | |1. -1
|2. 3| |-1. 3| |-1 2|
After Evaluating The Determinant of each 2x 2 Matrix
You'll have
[ 5 7 -3]
[3 5 -2 ]
[-1 -2 1]
Reflect this along the diagonal( Keep 5,5 -2)
Then switching positions of other value
No need of Multiplying by the determinant because its value is 1 from calculation.
After this
Our Inverse Matrix Would be
[ 5 3 -1 ]
[7 5 -2 ]
[ -3 -2 1]
THIS IS OUR INVERSE.
SO
OPTION C
Answer:
No real solution
Step-by-step explanation:
There is no perfect squares in 50
Well, since their are four options, and Jamal is likely to pick any of them, 25% is the answer. 25 is also 1/4.
Answer:
y=1x +8
5
Step-by-step explanation:
y-y1 = m(x-x1)
y+2 = -5(x-2)
y+2 = -5x + 10
y = -5x +8
Now to find line L we have to change the slope because it is perpendicular
y= 1x +8 (The slope is one fifth, but idk
5. to put it, I'm sorry)
