Question

Show your work please . NO LINKS.​

Answer 1

Answer:

i x = 0

ii x = 5,9

iii y = 12

iv y = 0

Step-by-step explanation:

0 = 12x²/(x - 5)(x - 9)

0 = 12x²

0 = x²

x = 0

ii vertical asymptotes at x = 5, 9

asymptotes occur as either term (x - 5)(x - 9) approaches zero

iii horizontal asymptote y = 12

function essentially becomes 12(∞²)/∞² = 12(1) as x goes to ±∞

iv y = 0 where x = 0