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gtnhenbr [62]
3 years ago
7

PLEASE HELP ASAP 1-5 THANK YOU!!!

Mathematics
2 answers:
stepladder [879]3 years ago
8 0

Answer:

1. $120

2. 8 hours

3. $15

4. $30/hr

don't know what #5 is

Dafna1 [17]3 years ago
4 0

Answer:

1a

2c

3c

4a

5d

hope this helps

Step-by-step explanation:

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What is the area of the triangle
Reika [66]
Base x height divided by 2
10x8=80
80÷2=40
area=40
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3 years ago
Simplify the expression below. (2n/6n+4)(3n+2/3n-2)
andrezito [222]

Answer:

\frac{n}{3n-2}

Step-by-step explanation:

Given the expression:

\frac{2n}{(6n+4)} \cdot \frac{3n+2}{3n-2}

Using the distributive property: a \cdot (b+c) =a\cdot b+a\cdot c

\frac{2n}{2(3n+2)} \cdot \frac{3n+2}{3n-2}

Simplify:

\frac{2n}{2} \cdot \frac{1}{3n-2}

Simplify:

\frac{n}{3n-2}

Therefore, the simplified given expression is, \frac{n}{3n-2}

7 0
3 years ago
Read 2 more answers
Somebody give me the answer to this
jeka57 [31]

Answer:

-2v = (-2x3, -2x4) = (-6,-8)

4 0
3 years ago
One year Perry had the lowest ERA​ (earned-run average, mean number of runs yielded per nine innings​ pitched) of any male pitch
Blizzard [7]

Answer:

z score Perry z=-1.402

z score Alice z=-1.722

Alice had better year in comparison with Perry.

Step-by-step explanation:

Consider the provided information.

One year Perry had the lowest ERA​ of any male pitcher at his​ school, with an ERA of 3.02. For the​ males, the mean ERA was 4.206 and the standard deviation was 0.846.

To find z score use the formula.

z=\frac{x-\mu}{\sigma}

Here μ=4.206 and σ=0.846

z=\frac{3.02-4.206}{0.846}

z=\frac{-1.186}{0.846}

z=-1.402

Alice had the lowest ERA of any female pitcher at the school with an ERA of 3.16. For the​ females, the mean ERA was 4.519 and the standard deviation was 0.789.

Find the z score

where μ=4.519 and σ=0.789

z=\frac{3.16-4.519 }{0.789}

z=\frac{-1.359}{0.789}

z=-1.722

The Perry had an ERA with a z-score is –1.402. The Alice had an ERA with a z-score is –1.722.

It is clear that the z-score value for Perry is greater than the z-score value for Alice. This indicates that Alice had better year in comparison with Perry.

7 0
3 years ago
Show all work to identify the asymptotes and zero of the function f of x equals 5 x over quantity x squared minus 25.
Lorico [155]

Answer:

  • asymptotes: x = -5, x = 5
  • zero: x = 0

Step-by-step explanation:

The function of interest is ...

  f(x)=\dfrac{5x}{x^2-25}=\dfrac{5x}{(x-5)(x+5)}

The asymptotes are found where the denominator is zero. It will be zero when either factor is zero, so at x = 5 and x = -5

__

The zeros are found where the numerator is zero. It will be zero for x = 0.

The asymptotes are x=-5, x=5; the zero is x=0.

4 0
3 years ago
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