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MrMuchimi
2 years ago
15

Ms. Snyder is giving a 28-question test that is made up of multiple choice questions worth 2 points each and open response quest

ions worth 4 points each. The entire test is worth 100 points. Let x represent the number of multiple choice questions, and let y represent the number of open response questions.
Write a system of linear equations to represent each situation.
Mathematics
1 answer:
zlopas [31]2 years ago
8 0

Answer:

x *2 + (28-x)*4 = 100

Step-by-step explanation:

Given

Total number of questions in the paper = 28

Out of these 28 questions let us say that x number of questions are of 2 points and 28-x questions are of 4 points.

Also, the complete test is of 100 marks

Thus, the linear equation representing the

x *2 + (28-x)*4 = 100

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A survey with a two-point scale was conducted in an organization. It concluded that 85% of the respondents were unsatisfied with
Morgarella [4.7K]

Answer:

Number of the peoples were satisfied with the career guidance are 300 .

Step-by-step explanation:

Formula

Percentage = \frac{Part\ value\times 100}{Total\ value}

As given

A survey with a two-point scale was conducted in an organization.

It concluded that 85% of the respondents were unsatisfied with the career guidance they were provided.

If 2,000 people participated in the survey.

Total value = 2000

Percentage = 85%

Putting all the values in the formula

85 = \frac{Part\ value\times 100}{2000}

Part\ value= \frac{2000\times 85}{100}

Part\ value= \frac{170000}{100}

Part value = 1700

i.e

People not satisfied by the career guidance = 1700

People satisfied by the career guidance = Total people participated in survey  - People not satisfied by the career guidance .

Putting the values in the above

                                                                  = 2000 - 1700

                                                                  = 300

Therefore the number of the peoples were satisfied with the career guidance are 300 .


5 0
3 years ago
Read 2 more answers
(30 POINTS AND BRAINLIEST FOR BEST)
Romashka-Z-Leto [24]

Part A)

Multiply the amount he earned by 8.5%

8.5% written as a decimal is 0.085.

75,000 x 0.085 = $6,375

Part B)

Subtract the amount of tax from his earnings:

75,000 - 6,375 = $68,625

8 0
3 years ago
Linda goes water-skiing one sunny afternoon. After skiing for 15 min, she signals to the driver of the boat to take her back to
trasher [3.6K]
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2


abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.


d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
4 0
3 years ago
David weighs 20 pounds more than katie while jonathan weighs 120 pounds less than three times katie's weight if david and jonoth
ladessa [460]
D = k + 20
j = 3k - 120
d = j

k + 20 = 3k - 120
20 + 120 = 3k - k
140 = 2k
140/2 = k
70 = k.....so Katie weighs 70 lbs

David and Johnathan each weigh 90 lbs
3 0
3 years ago
Find an equation for the tangent to the curve at the given point y=x^3 , (2,8)
Yuliya22 [10]

\bf y=x^3\implies \left. \cfrac{dy}{dx}=3x^2 \right|_{x=2}\implies \stackrel{\stackrel{m}{\downarrow }}{12} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{2}~,~\stackrel{y_1}{8})~\hspace{10em} slope = m\implies 12 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-8=12(x-2) \\\\\\ y-8=12x-24\implies y=12x-16

5 0
2 years ago
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