<h2>
a. What is your equation?</h2>
This is a problem of projectile motion. A projectile is an object you throw with an initial velocity and whose trajectory is determined by the effect of gravitational acceleration. The general equation in this case is described as:
Where:
So:
Finally, the equation is:
<h2>b. How long will it take the rocket to reach its maximum height?</h2>
The rocket will reach the maximum height at the vertex of the parabola described by the equation 
. Therefore, our goal is to find 
at this point. In math, a parabola is described by the quadratic function:
So the x-coordinate of the vertex can be calculated as:
From our equation:
So:
So the rocket will take its maximum value after 1.99 seconds.
<h2>
c. What is the maximum height the rocket will reach?</h2>
From the previous solution, we know that after 1.99 seconds, the rocket will reach its maximum, so it is obvious that the maximum height is given by 
. Thus, we can find this as follows:
So the maximum height the rocket will reach is 66.68ft
<h2>
d. How long is the rocket in the air?</h2>
The rocket is in the air until it hits the ground. This can be found setting 
, so:
We can't have negative value of time, so the only correct option is 
and rounding to the nearest hundredth we have definitively:
625+625=1250
hope this helped
Answer:
<h2>C) (negative 1, one-half), (0, 1), (1, 2), (2, 4)</h2>
Step-by-step explanation:
The set C could be generated by an exponential function. The main reason is that exponential functions hava a restricted range, it can't have negative numbers or the number zero, because power can only be equal or greater than 1.
Additionally, for all exponentials, a null exponent gives 1 as an answer, so point (0, 1) is always present in an exponential function.
Therefore, the right answer is C.
The answer would be standard deviation.
Answer:
[x] f(x)
[-6] 13
[-3] 4
[0] 1
[3] 4
[9] 28
Step-by-step explanation:
f(0) = (1/3)(0^2)+1 = 1
f(3) = (1/3)(3^2)+1 = 4
f(9) = (1/3)(9^2)+1 = 28
