We are given the function
F(x) = 9 sinx + cot x
We need to take the first derivative of the given function so,
F' (x) = 9 cos x - csc² x
Next, we equate the first derivative of the function to 0 and solve for the values of x
0 = 9 cos x - csc² x
Solving for x
x = 2.04
Picking out an arbitrary value between 2.04 and π, say 3 and substituting in F(x)
F(3) = 9 sin 3 + cot 3 = 19.55
Therefore, the interval where the function is increasing is from 2.04 to π
Consequently, the interval where the function is decreasing is from -π to 2.04<span />
At very minimum, move (4/5)x to the other side of the given equation. Then:
-(4/5)x + y = 0.85. This is the equation in standard form.
Plug in 6 for x
2^2 - 7(6) - 6
4 - 42 - 6 = -44
A divide by sin A =b divide by sinB
3 divide by sin 20= AB divide by sin 90
AB=sin 90 times 3 divide by sin 20
=8.77 cm
