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BabaBlast [244]
3 years ago
8

What is the product? 3x^5(2x^2+4+1)

Mathematics
1 answer:
const2013 [10]3 years ago
5 0

Answer:

6x^{7} +15x^{5}

Step-by-step explanation:

3x^{5}(2x^{2} +4+1)

Multiply 3x^{5} by each term in the parentheses.

6x^{7} + 12x^{5} +3x^{5}

Now, all you have to do is simplify.

6x^{7} +15x^{5}

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What is the solution to the equation –13+x = –4?<br> a. –17<br> b. 9<br> c. –9<br> d. 17
Debora [2.8K]
-13+9=-4
When you add a positive number to a negative number the answer will get closer to 0 and then progress up in positive numbers. In this case we are finding which of the numbers equals -4 when added to -13. Remember, if you add a negative to a negative you will get a negative.
-13+-17=-30 This is the wrong answer.
-13+-9=-21 This is the wrong answer.
-13+17=4 This is the wrong answer. (This is positive 4 we are trying to find -4)
-13+9=-4 This is the right answer
Therefore X=9
6 0
3 years ago
Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,
Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is \dfrac{1}{6} = 0.1667 .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is   \dfrac{1}{6} .

      Numbers on the dice (X)                       P(X)

                      +1                                                 \frac{1}{6}

                      +2                                                \frac{1}{6}

                      +3                                                \frac{1}{6}

                      -4                                                 \frac{1}{6}

                      +5                                                \frac{1}{6}

                      -6                                                 \frac{1}{6}

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X)  =  \sum X \times P(X)

   =  (+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}

   =  \frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}

   =  \frac{1+2+3-4+5-6}{6}

   =  \frac{11-10}{6}= \frac{1}{6}

Hence, the expected value of the points earned on a single roll in this game is  \frac{1}{6} = 0.1667 .

4 0
3 years ago
Mohit pays rupees 9000 as an amount on the sum of rupees 7000 that he had borrowed for 2 years.
Sphinxa [80]

Answer:

The required rate of interest   =   14.285%

Step-by-step explanation:

Here, The principal amount = 7,000

The final paid amount = 9,000

Time = 2 years

Let us assume the rate of interest = R

Now, Simple Interest  =  Amount - Principal

                                      =  9,000 - 7,000  = 2,000

So, the SI on the given principal for 2 years  = 2,000

\textrm{SIMPLE INTEREST } = \frac{P \times  R \times T}{100}\\\implies 2000 = \frac{7,000 \times  R \times 2}{100}\\\implies R = \frac{2,000 \times 100}{7,000 \times 2}  = 14.285

or, R =  14.285%

Hence, the required rate of interest   =   14.285%

8 0
3 years ago
Suppose that the mean score of a class of 32 students was 74. the 19 male students in the class had a mean score of 70. what was
andrew-mc [135]
Mean = sum of values / number of values
74 = x/32
2368 = x

70 = y/19
1330 = y

mean for female students = (2368 - 1330)/(32-19) = 79.85
5 0
3 years ago
Help?!<br> ???????????LK
Katarina [22]

Answer:

Equation: 65+1.50m=78.50

Solution to the equation= 9 minutes

Step-by-step explanation:

The parents have to give 65 dollars for their children to be under care till 6 o'clock. AFter 6 o'clock, they had to pay 1.50 dollars for one minute. This parent gives a total of 78.50 dollar for that day. So, the equation is :

65+1.50m=78.50

(btw, m stands for minutes)

So to solve the equation:

1.50m=13.50

m= 9

3 0
3 years ago
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