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3 years ago

What is 4x-2y=8 in slope intercept form?

Mathematics

2 answers:

vladimir1956 [14]3 years ago

8 0

Answer: y = -2x + 4

Step-by-step explanation: In slope-intercept form or y = mx + b form,

the y is isolated or by itself on the left side of the equation.

So start by subtracting 4x from both sides.

That gives us -2y = 4x - 8.

Notice I put the x term first because in y = mx + b form,

the x term comes first on the left side of the equation.

From here, we divide both sides by -2 to get y = -2x + 4.

DerKrebs [107]3 years ago

6 0

Slope form is y=mx+b
Y=2x-4
m=2, b= -4

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3 years ago

A diameter of a circle has enpoints (-2, 10) and (6, -4) in the standard (x, y) coordinate plane. What is the center of the circ

wlad13 [49]

Answer:

The center of the circle is $C(x,y) = (2, 3)$ .

Step-by-step explanation:

The center of the circle is the midpoint of the segment between the endpoints. We can determine the location of the center by this vectorial expression:

$C(x,y) = \frac{1}{2}\cdot R_{1}(x,y)+ \frac{1}{2}\cdot R_{2}(x,y)$ (1)

Where:

$C(x,y)$ - Center.

$R_{1} (x,y)$ , $R_{2} (x,y)$ - Location of the endpoints.

If we know that $R_{1} (x,y) = (-2,10)$ and $R_{2} (x,y) = (6,-4)$ , then the location of the center of the circle is:

$C(x,y) = \frac{1}{2}\cdot (-2,10)+\frac{1}{2}\cdot (6,-4)$

$C(x,y) = (-1, 5) + (3, -2)$

$C(x,y) = (2, 3)$

The center of the circle is $C(x,y) = (2, 3)$ .

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3 years ago

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Step-by-step explanation:

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Answer:

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