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3 years ago

I need help with these please

Mathematics

1 answer:

Kipish [7]3 years ago

8 0

Answer:

Q1 (-2,-5)(0,3)(4,19)(7,31)

Step-by-step explanation:

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Please help due in 5 minutes

soldier1979 [14.2K]

Answer:

(-1,-2)

Step-by-step explanation:

There is a solution where the two expressions intersect. We can plug in what we know in the first equation in the second.

x= -1

y=3x+1

y= 3(-1)+1

y= -3+1

y= -2

Plugging y value in the equation to find x:

-2=3x+1

-3=3x

x= -1

Therefore, the point is (-1,-2)

I hope this helps! :)

5 0

3 years ago

Read 2 more answers

Jared has $18 to spend. He buys lunch for $3.87 and a tie for $5.95. Jared buys a magazine with the remaining money. How much do

AleksandrR [38]

3.87 + 5.95 = 9.82
18 - 9.82 = 8.18

8 0

4 years ago

Read 2 more answers

Scott bought a backpack for $35.99 at Walmart. He needed to pay a 10% tax. How much did the backpack cost in all?

stellarik [79]

$35.99 x .10=3.599
$35.99 + 3.60=$39.59

8 0

4 years ago

The heights of a maple tree and a cherry tree have a ratio of 5:2. If the maple tree grew 20 cm and 20 cm was cut off the top of

elena-14-01-66 [18.8K]

Let x be the heights of a maple tree and y be the height of the cherry tree.
We know:
 $\frac{x}{y} = \frac{5}{2}$
The new ratio is obtained like this:
 $\frac{x+20}{y-20} = \frac{3}{1}$ .
From the above equation we get $x= (y-20)\frac{3}{1} -20$ .
then $\frac{ (y-20)\frac{3}{1} -20}{y} = \frac{5}{2}$
Solving the above equation for y we get: $y=160$
So $x=400$
So the first tree is (400-160=240) more taller than cherry tree.

7 0

3 years ago

HELP ASAP PLEASE

Stels [109]

Solution (1) using angles of sectors:

Area of A = pi r^2 x 90/360 = 4.9

Area of B = pi r^2 x 270/360 = 14.2

Check: Area of A/B = 4.9/14.72 = 1/3 (as given)

Solution (2) using given info:

Area of B + Area of A = area of circle

Area of B + 1/3 Area of B = 3.14 * (2.5)^2 = 19.625

4/3 Area of B = 19.625

Area of B = 3/4 * 19.625

Area of B = 14.72

Area of A = 1/3 * 14.72 = 4.9

There is more solutions to this problem , like polar coordinate integration , and so on. for more just request.

8 0

3 years ago