Step-by-step explanation:
Hey there!!!
Here,
Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.
The equation of a straight line passing through point is,

Now, put all values.

It is the 1st equation.
Another equation is;
y = 5x +2........(2nd equation).
Now, Comparing it with y = mx + c, we get;
m2=5
As per the condition of perpendicular lines,
m1×m2= -1
m1 × 5 = -1
Therefore, m2= -1/5.
Keeping the value of m1 in 1st equation.

Simplify them.



Therefore the required equation is x+5y+8= 0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
a.
Step-by-step explanation:
Answer:
84
Step-by-step explanation:
First you multiply 2 and 7
Ans 14
Then you multiply 14 and 6
Ans 84
Since the graph is a straight line, we know that this equation follows some sort of y = mx + b format.
Let's take the points that are on the axes (-4,0) and (0,-3)
use them to find the slope = (0 - (-3))/(-4 - 0) = 3/(-4) = -3/4
this is our m in the general equations above
we now have y = (-3/4)x + b
b is the y-intercept which is where x = 0 we already have that point in (0,-3)
plug the -3 in for b to give as a final answer:
y = (-3/4)x - 3