Answer:
Rise: 200.25
Descent 300.2
Minutes
Step-by-step explanation:
A) We are using the Pythagorean theorem for the climb and descent. (a^2 + b^2 = c^2)
For climb a = 200, b = 10 c = ?
200^2 + 10^2 = c^2 = 40000 + 100 = c^2 = 40100 = c^2
c = about 200.25
For the descent: a = 300, b = 10
300²+10² = c²
90000 + 100 = c²
90100 = c²
c = about 300.2
B) If a plane is going 600 km/h and it goes about 10 km that means the plane is only going for 10/600 of an hour.
10/600 is 1/60, so only a couple minutes difference.
Answer:
The equations [(-5) + (-3)] + 6 = -2 and [6 + (-5)] + (-3) = -2 he can use to find the sum of the temperatures for those months ⇒ 3rd , 5th
Step-by-step explanation:
i took the assignment
Answer:
I think it is a and f i could be wrong
Step-by-step explanation:
Answer:
Yes it really does mean cup.
Step-by-step explanation:
This can only contian 1 jar
12.5 cups are equal to 100 ounces
if there are 100 oz in that little jar then only 1 large jar can be filled by a lttile jar.
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P