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tia_tia [17]
3 years ago
6

ReeeeeeeeeeeereEeeeeereeeee

Mathematics
2 answers:
love history [14]3 years ago
8 0
12/2+(6-2)^2

6+(4)^2

6+16=22

Best of luck!!
zhenek [66]3 years ago
4 0

Answer:

22

Step-by-step explanation:

B racket

I ndices

D division

M multiplication

A addition

Subtraction

Work out answer using the BIDMAS order

You might be interested in
Suppose you waited 10 years to invest in the same retirement fund and have the same $400,000 for retirement at the same 8% inter
Ierofanga [76]

Answer:

<em>$7,196.42 </em>

Step-by-step explanation:

Using the compound interest formula to fins the amount after 10years;

A  = P(1+r)^n

Principal P = $400,000

Rate r = 8% = 0.08

Time t = 10 years

Substitute

A = 400,000(1+0.08)^10

A = 400,000(1.08)^10

A = 400,000(2.1589)

A = 863,569.99

A ≈ 863,570

Hence the amount after 10 years is $863,570

Monthly deposit = $863,570/120 (10 years is equivalent to 120months)

Monthly deposit = 7,196.42

<em>Therefore he will have to deposit $7,196.42 into his account monthly</em>

7 0
3 years ago
I need m and b help please
nirvana33 [79]
It took me awhile but I got it

m= -2/7
b=5 5/7


or

y=-2/7x+5 5/7
6 0
3 years ago
Read 2 more answers
Yogurt is an ever more popular food item. In 2002, American Dairy affiliates produced 2133 million pounds of yogurt. In 2007, th
Valentin [98]
You would write your 2 ordered pairs based on the year and the amount of yogurt sold in that year.

The x-value (your first number in the ordered pair) the year and the y-value (the 2nd number in the ordered pair) the amount of yogurt.

(2002, 2133) and (2007, 3478) would be your 2 ordered pairs.
4 0
3 years ago
Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=
luda_lava [24]

Let f(x) = x^3 - 2x - 2. Then differentiating, we get

f'(x) = 3x^2 - 2

We approximate f(x) at x_1=2 with the tangent line,

f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18

The x-intercept for this approximation will be our next approximation for the root,

10x - 18 = 0 \implies x_2 = \dfrac95

Repeat this process. Approximate f(x) at x_2 = \frac95.

f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}

Then

\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}

Once more. Approximate f(x) at x_3.

f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}

Then

\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}

Compare this to the actual root of f(x), which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0
2 years ago
the nutritional chart on the side of a box of cereal states that there are 93 calories in a 3/4 cup serving how many calories ar
elixir [45]

5 / 3/4 = 5/1 * 4/3 = 20/3 = 6 2/3


6 2/3 * 93 = 20/3 * 93/1 = 1860/3 = 620 calories

7 0
4 years ago
Read 2 more answers
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