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3 years ago

A cylindrical tube has a radius of 4 inches and a height of 14 inches could some one help me find the volume

1 answer:

8 0

The volume of the cylinder is the area of the base (a circle) times the height (you can immagine taking a disk, the base, and translate it along the height to "fill" the cylinder).
So you have:
$V=area.circle*height= \pi r^{2}*h = \pi 4^{2} *14=703.4 in^{2}$

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URGENT!!! PLEASE LOOK AT THE PICTURE!!! PLEASE HELP!!!!

Svetllana [295]

Answer:

Step-by-step explanation:

this is a 45-45-90 triangle. The angle opposite the 45° angle is also 45°.

HI = HJ because this is an isosceles triangle.

Use the cos function to find the length of HJ:

cos Ф = adj / hyp or adj = (hyp)(cos Ф).

Here we have adj = HI = HJ = 4√5 cos 45° = 4√5 · -----

√2, or 4√5 / √2

4√10

This last result simplifies to ----------

or 2√10 (answer)

The length of side HJ and that of HI is 2/√10.

7 0

3 years ago

A ball is thrown downward from a cliff. Its position at time t seconds is given by the formula s(t) = 16t2 + 32t, where s is in

Rom4ik [11]

Answer:

It takes 2.8 seconds for the ball to fall 215 ft.

Step-by-step explanation:

We are given a position function s(t) where s stands for the number of feet the ball has fallen, so we have to replace s with the given value of 215 ft and solve for the time t.

Setting up the equation.

The motion equation is given by

$s(t) =16t^2+32t$

We can replace there s = 215 ft to get

$215=16t^2+32t$

Solving for the time t.

From the previous equation we can move all terms in one side to get

$16t^2+32t-215=0$

At this point we can solve for t using quadratic formula.

$t = \cfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

where a, b and c are the coefficients of the quadratic equation

$at^2+bt+c=0$

So we get

$a=16\\b=32\\c=-215$

Replacing on the quadratic formula we get

$t = \cfrac{-32\pm \sqrt{32^2-4(16)(-215)}}{2(16)}$

Using a calculator we get

$t=-4.8 , t = 2.8$

Physically speaking the only result that makes sense is to move forward in time that give us t = 2.8 seconds.

We can conclude that it takes 2.8 seconds for the ball to fall 215 ft.

3 0

3 years ago

I need help please I don’t get it

Aliun [14]

Answer: left 9 and up 6

Step-by-step explanation:

just if it’s in the bars it’s left if + and on the outside its up if +

3 0

3 years ago

A scuba diver is at an elevation of −18 ft. She then descends 30 ft deeper. What is the scuba diver's new elevation?

sladkih [1.3K]

-18 - 30 = -48
The Scuba Diver is now 48 feet below sea level.

7 0

2 years ago

Use Simpson's Rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. Compare y

DiKsa [7]

The area of the surface is given exactly by the integral,

$\displaystyle\pi\int_0^5\sqrt{1+(y'(x))^2}\,\mathrm dx$

We have

$y(x)=\dfrac15x^5\implies y'(x)=x^4$

so the area is

$\displaystyle\pi\int_0^5\sqrt{1+x^8}\,\mathrm dx$

We split up the domain of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [4, 9/2], [9/2, 5]

where the left and right endpoints for the $i$ -th subinterval are, respectively,

$\ell_i=\dfrac{5-0}{10}(i-1)=\dfrac{i-1}2$

$r_i=\dfrac{5-0}{10}i=\dfrac i2$

with midpoint

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

with $1\le i\le10$ .

Over each subinterval, we interpolate $f(x)=\sqrt{1+x^8}$ with the quadratic polynomial,

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

Then

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that the latter integral reduces significantly to

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\frac56\left(f(0)+4f\left(\frac{0+5}2\right)+f(5)\right)=\frac56\left(1+\sqrt{390,626}+\dfrac{\sqrt{390,881}}4\right)$

which is about 651.918, so that the area is approximately $651.918\pi\approx\boxed{2048}$ .

Compare this to actual value of the integral, which is closer to 1967.

4 0

3 years ago