-141/8
using BODMAS you open the bracket
-17/8 -31/2
Now expand the fraction in the first photo above
-17-124/8
-141/8 or 17.625
A) 2L + 2W = 48
B) L * W = 140
B) W = 140 / L
Inputting this to equation A)
A) 2L + 2*(140 /L) = 48
L + 140/L = 24
Multiplying both sides by "L"
L² + 140 = 24L
L² -24L +140 = 0
(L -10) * (L-14) = 0
L= 10
L = 14
If length = 10 then width =14
If length = 14 then width = 10
The GCF is <span>1. hope that helps</span>
Answer:
0.85
Step-by-step explanation:
Given two events A and B, the probability that either A or B occurs is given by:
where
the probability that A occurs
is the probability that B occurs
is the probability that both A and B occur at the same time
In this problem, we know the following facts:
is the probability that the car requires an oil change
is the probability that the car requires a brake repair
is the probability that the car requires both an oil change and brake repair
Therefore, the probability that either o (car requiring oil change) or b (car requiring brake repait) occur is:
