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xenn [34]
3 years ago
15

What is the 20th term for the following sequence? 3,-9, 27,-81, ...

Mathematics
1 answer:
anygoal [31]3 years ago
8 0

Answer: -3486784401

Step-by-step explanation:

This is a geometric progression and the formula to use to find the nth term will be: = ar^(n-1)

where,

a = 3

r = -9/3 = -3

n = 20

Therefore, ar^(n-1)

= 3 × -3^19

= 3 × -1162261467

= -3486784401

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kipiarov [429]
800 divided by 50 = 16 ...... 16 x 22 = C.448
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4 years ago
Read 2 more answers
SOMEONE PLEASE HELP QUICK
Viktor [21]
X can be any number in the graph as long as it is on the x-axis therefore you can put x as -1,0 and 1. Then you would need to replace the ‘x’ in the equation so it would look like y=-2*1+3. You replace ‘x’ with every number you put in the x boxes. Then just solve the equations

y=-2*1+3
Y=-2*0+3
Y=-2*-1+3
They would give you the y axis coordinates so then you just put them together for the middle column.

Answer

y=-2*1+3=1
Y=-2*0+3=3
Y=-2*-1+3=5

Coordinates are (1,3) (0,3) (-1,5)
4 0
3 years ago
Solve each of the following equations by the trial and error method : A) X- 7= -3 help some one now​
Vaselesa [24]

Answer:

X - 7 = - 3

X = - 3 + 7

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- becomes +

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+ becomes -

8 0
3 years ago
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maria [59]

Answer:

22π in.

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8 0
3 years ago
Maddie biked 8 3/4 miles today, and Chase bikes 3 1/2 miles. How many times the length of Chase’s bike ride was Maddie’s bike ri
borishaifa [10]

Answer: 2.5 times

Step-by-step explanation:

Given : The length of Chase’s bike ride= 8\dfrac{3}{4}\ miles

The length of Maddie’s bike ride=3\dfrac{1}{2}\ miles

In improper fraction : Length of Chase’s bike ride=\dfrac{4(8)+3}{4}\ miles

=\dfrac{35}{4}\ miles

Similarly , Length of Maddie’s bike ride= \dfrac{7}{2}\ miles

The number of times the length of Chase’s bike ride was Maddie’s bike ride= \dfrac{\text{ Length of Chase’s bike ride}}{\text{ Length of Maddie’s bike ride}}

=\dfrac{\dfrac{35}{4}}{\dfrac{7}{2}}\\\\=\dfrac{5}{2}=2.5

Hence, the length of Chase’s bike ride was 2.5 times Maddie’s bike ride.

8 0
3 years ago
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