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Afina-wow [57]
3 years ago
11

2 x10^14/8x10^9 How do you solve

Mathematics
1 answer:
Rom4ik [11]3 years ago
4 0

Answer:

Step-by-step explanation:

\frac{2*10^{14}}{8*10^{9}}=\frac{1}{4}*10^{14-9}=\frac{1}{4}*10^{5}\\\\\\\frac{a^{m}}{a^{n}}=a^{m-n}\\\\

In exponent division , if bases are same, then find the difference of the exponents

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choli [55]

Answer: 12

Step-by-step explanation:

\frac{6}{18}=\frac{4}{c}

Solve for c

c=\frac{4*18}{6}\\ c=\frac{72}{6} \\c=12

3 0
3 years ago
A graduated cylinder is filled with 36\pi36π36, pi cm^3 3 start superscript, 3, end superscript of liquid. The liquid is poured
lilavasa [31]
By definition, the volume of a cylinder is given by:
 V = π * r ^ 2 * h
 Where,
 r: cylinder radius
 h: height
 Clearing h we have:
 h = (V) / (π * r ^ 2)
 Substituting values:
 h = (36π) / (π * 3 ^ 2)
 h = (36π) / (9π)
 h = (36π) / (9π)
 h = 4 cm
 Answer:
 
The height of the liquid will be in the new cylinder about:
 
h = 4 cm
5 0
3 years ago
Read 2 more answers
What is b’c the length of bc after dilation? What is the measure of
Anastasy [175]

Answer:

C

Step-by-step explanation:

the angle will always stay the same, it won't change

but if the dialation is 1/2, then that means that the sides will decrease in size compared to the original length,

(just divide by 2) on each side length to get the answer

4 0
3 years ago
What’s the 5th term is 2,14,98
iragen [17]

\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
  • <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

  • \sf{a1\: or \:1st\: term = 2 }
  • \sf{a2 \:or \:2nd\: term = 14 }
  • \sf{an \:or\: last\: term = 98}

<u>Here</u><u>, </u>

Common difference of an AP

\sf{ a2 - a1 }

\sf{ = 14 - 2}

\sf{ = 12}

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

Hence, The 5th term of given AP is 50

4 0
2 years ago
Help asap, please
makkiz [27]

Answer:

triangle ABC was translated up 4units and left 4 units

Step-by-step explanation:

8 0
3 years ago
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