Answer:
Step-by-step explanation:
Answer:
Factoring
Step-by-step explanation:
and 
The missing justification in Julia's angle proof is; Corresponding Angles Theorem
<h3>What is the angle theorem used?</h3>
We know that m∠AGE ≅ m∠HGB because they have congruent angles and are vertical angles.
Similarly, m∠HGB ≅ m∠CHE are alternate interior angles because two congruent angles on the inner side of the parallel lines are formed by a transversal.
In the diagram, m∠AGE ≅ m∠CHE would have to be corresponding Angles Theorem because parallel lines cut by a transversal would create congruent corresponding angles. That means a pair of angles on the same side of one of two lines that is cut by a transversal and on the same side of the transversal.
Read more about Angle theorem at; brainly.com/question/24839702
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Answer:
divided by 6
Step-by-step explanation:
Given pattern
360,60,10
would it be add 60
lets
add 60 to each term
360 +60 = 420
but next term is 60, hence it incorrect choice
divided by 6
lets divide each term by 6
360/6 = 60 which is the next term in the series as well
60/6 = 10 which is also the next term in the series as well
hence divided by 6 is the correct option.
multiply by 6
multiply by 6 to each term
360 *60 = 21600
but next term is 60, hence it incorrect choice
subtract 60 from each term
360 -300 = 60 which is the next term in the series
60 -300 = -240 which is not same the next term in the series that is 10
hence this is incorrect choice
Answer:
So the end points of the mid segment are:
S
T
Step-by-step explanation:
First of all we need to list the co-ordinates of the points of the triangle shown.
P
Q
R
We need to find mid segment of the triangle which is parallel to segment PQ. This would mean we need to find midpoints of segment PR and QR and then join the points to get mid segment.
Midpoint Formula:
Midpoint of PR:
S(
S
Midpoint of QR:
T
T
So the end points of the mid segment are:
S
T
By mid segment theorem we know that the line joining midpoints of two sides of a triangle is parallel to the 3rd side.
∴ We know ST is parallel to PQ
