D + q = 32....d = 32 - q
0.10d + 0.25q = 6.50
0.10(32 - q) + 0.25q = 6.50
3.20 - 0.10q + 0.25q = 6.50
-0.10q + 0.25q = 6.50 - 3.20
0.15q = 3.30
q = 3.30 / 0.15
q = 22 <=== 22 quarters
d + q = 32
d + 22= 32
d = 32 - 22
d = 10 <=== 10 dimes
Answer:
6.51 cm
Step-by-step explanation:
Since the sphere causes the water level in the cylindrical container to rise and thus increase by its own volume, the volume of the sphere is V = 4πr³/3 where r = radius of sphere. The volume rise of the container is thus V' = πR²h where R = radius of base of cylinder = 7 cm and h = height of water level = 7.5 cm.
Since V = V',
4πr³/3 = πR²h
dividing through by π, we have
4r³/3 = R²h
multiplying both sides by 3/4, we have
r³ = 3R²h/4
taking cube-root of both sides, we have
r = ∛(3R²h/4)
Substituting the values of the variables into the equation, we have
r = ∛(3(7 cm)² × 7.5 cm/4)
r = ∛(3 × 49 cm² × 7.5 cm/4)
r = ∛(1102.5cm³/4)
r = ∛(275.625 cm³)
r = 6.508 cm
r ≅ 6.51 cm to 2 decimal places
80 cups in a 5 gallon jug of water.
1 quart has 4 cups
1 gallon has 4 quarts
1 gallon = 4 quarts * 4 cups = 16 cups
5 gallons = has 80 cups of water.
(4 cups / 1 quart) x (4 quarts / 1 gallon) x (5 gallons) = 4 x 4 x 5 = 80 cups <u>
</u>
Answer:
t = 6/5
Step-by-step explanation:
Step 1: Define
k(t) = 10t - 19
k(t) = -7
Step 2: Substitute and Evaluate
-7 = 10t - 19
12 = 10t
t = 6/5
