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Reil [10]
3 years ago
15

Mr.Williams, a parking lot owner, sold 20% of his lot to his neighbor. Later that year he sold 20% of the remainder of his lot t

o another neighbor. What percent of Mr.Williams' original parking lot does he still own?
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
4 0

Answer: He still owns 64% of the Mr.Williams' original parking.

Step-by-step explanation:

Let x = Area of the original parking plot.

First he sold 20% of his lot to neighbor .

Sold plot = 20% of x = 0.20x  [Replace 'of' by '×' and divide number by 100 to remove %]

Reminder= x-0.20x= (1-0.20)x=0.80x

Again he sold 20% of the remainder .

Sold plot = 20% of (0.80x) = 0.20 (0.80x)

= 0.16x

Remainder plot = 0.80x-0.16x= 0.64x

Percent of Mr.Williams' original parking lot does he still own = \dfrac{0.64x}{x}\times100=64\%

Hence, he still owns 64% of the Mr.Williams' original parking.

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A cake decorator rolls a piece of stiff paper to form a cone. She cuts off the tip of the cone and uses it as a funnel to pour d
Nimfa-mama [501]

Answer:

Step-by-step explanation:

Use the formula for volume of a cone

V = 1/3 pi r^2 (h)

V = 1/3 pi 66^2 (18)

V= 1/3 pi 4356(18)

V = 1/3 pi 78408

V = 1/3 264,201.12

V = 82,067.04cm^3

5 0
3 years ago
What is the HCF and LCM of 268 and 244​
Ray Of Light [21]

Answer:

HCF = 4

LCF = 16348

HOPE THIS HELPS :)

5 0
3 years ago
The area of a trapezoid is 168cm2. The height is 16cm and the length of one of the parallel sides is 9cm. Find the length of the
dmitriy555 [2]

Answer:

12 cm

Step-by-step explanation:

The formula for the area of a trapezoid is written as:

1/2(b1 + b2)h

h = height = 16 cm

b1 = Length of one parallel side = 9cm

b2 = Length of second parallel side = ?

Area of trapezoid = 168cm²

The formula to find the length of the second parallel side =

b2 = 2A/h - b1

b2 = 2 × 168/16 - 9

b2 = 336/16 - 9

b2 = 21 - 9

b2 = 12cm

Therefore, the length of the second parallel side is 12 cm

3 0
3 years ago
Which trigonometric function has a range that does not include 0.4?
Montano1993 [528]
<h2>Hello!</h2>

The answer is: y=cscx

<h2>Why?</h2>

Domain and range of trigonometric functions are already calculated, so let's discard one by one in order to find the correct answer.

The range is where the function can exist in the vertical axis when we assign values to the variable.

First:

y=cosx: Incorrect, it does include 0.4 since the cosine range goes from -1 to 1 (-1 ≤ y ≤ 1)

Second:

y=cotx: Incorrect, it also does include 0.4 since the cotangent range goes from is all the real numbers.

Third:

y=cscx: Correct, the cosecant function is all the real numbers without the numbers included between -1 and 1 (y≤-1 or y≥1).

Fourth:

y=sinx : Incorrect, the sine function range is equal to the cosine function range (-1 ≤ y ≤ 1).

I attached a pic of the csc function graphic where you can verify the answer!

Have a nice day!

8 0
3 years ago
The magnitude of vector a = (5,m) is 13 and the magnitude of vector b = (n, 24) is 25. What are m and n
Ulleksa [173]

Answer:

m=12\,,n=7

Step-by-step explanation:

The magnitude of vector (x,y) is given by \sqrt{x^2+y^2}

The magnitude of vector a=(5,m) is 13.

\sqrt{5^2+m^2}=13\\5^2+m^2=13^2\\25+m^2=169\\m^2=169-25\\m^2=144\\m=12

The magnitude of vector b=(n,24) is 25.

\sqrt{n^2+24^2}=25\\n^2+24^2=25^2\\n^2+576=625\\n^2=625-576\\n^2=49\\n=7

Therefore,

m=12\,,n=7

5 0
3 years ago
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