4y - 3 = y + 6
Add 3 to both sides
4y = y + 9
Subtract y from both sides
3y = 9
Divide both sides by 3
y= 3
1) 2x(x+3)
2) 3xy^2(9-4y)
3) 5xy(x^2+2y)
4) 8ab(2a+3b)
5) 4ac^3(3b^2+4c)
Event A: The sum is greater than 5.There are 10 sums equal to 5 or less. Therefore there are 26 sums greater than 5.P = 26/36
Event B: The sum is divisible by 4.The sums that are divisible by 4 are the<span> three</span> 4's, five 8's, and the <span>one </span>12.That means there are nine sums divisible by 4. P = 9/36
