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Nikitich [7]
3 years ago
7

Is the following a function?

Mathematics
2 answers:
saw5 [17]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

For the relation to be a function, there must only be one corresponding value of y (range) for any value of x in the domain, that is a one-to- one relationship

This graph displays this feature and is a function.


Delicious77 [7]3 years ago
5 0

Answer:

yes it's a function

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Breanna works in the mall and her hours increase during busy shopping times of the year. Breanna has a plan to save $25 each wee
vesna_86 [32]
The math I used is probably not the quickest way, but for me, the easiest.
25*5=125  25+20=45  45*7=315  125+315=440  25*4=100  440+100=540  5+7+4=16
B is your answer.
5 0
3 years ago
Read 2 more answers
Sorry for the little blur but number 18 please! And sorry for the work mess. Start where it says *Start Here*
motikmotik
You are almost done!
well, the euation of a circle centered at (h,k) and radius r is
(x-h)²+(y-k)²=r²

so you havve
(x-3)²+(y+5)²=9 (which is correct)
this can be rewritten as
(x-3)²+(y-(-5))²=3²
the center is (3,-5) and the radius is 3
5 0
3 years ago
Geometry <br> What is the range of possible values for x? The diagram is not to scale.
Rom4ik [11]
Where is the diagram? How do we answer without it?
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7Dx%20-%208%3D%5Cfrac%7B1%7D%7B3%7D%283x-15%29" id="TexFormula1" title="\fr
tresset_1 [31]

Answer:

x= -18

Step-by-step explanation:

Solve for  

x

by simplifying both sides of the equation, then isolating the variable.

7 0
3 years ago
Read 2 more answers
Part 1: How's the weather? A. Investigate the weather forecast in your city. Record the high and low temperatures that are forec
victus00 [196]

Using the mean concept, it is found that:

1. The mean change in the forecasted high temperatures is of -0.33ºC.

2. The mean change in the forecasted low temperatures is of 0.5ºC.

-----------------------------

The mean of data-set is given by the <u>sum of all observations divided by the number of observations.</u>

Item 1:

The changes in the high temperature are: 2, 1, -1, -1, -1, -2

Thus:

M = \frac{2 + 1 - 1 - 1 - 1 - 2}{6} = -0.33

The mean change in the forecasted high temperatures is of -0.33ºC.

Item 2:

The changes in the low temperature are: 2, -2, 2, 1, 0, 0.

M = \frac{2 - 2 + 2 + 1 + 0 + 0}{6} = 0.5

The mean change in the forecasted low temperatures is of 0.5ºC.

A similar problem is given at brainly.com/question/24754716

3 0
2 years ago
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