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Nikitich [7]
3 years ago
7

Is the following a function?

Mathematics
2 answers:
saw5 [17]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

For the relation to be a function, there must only be one corresponding value of y (range) for any value of x in the domain, that is a one-to- one relationship

This graph displays this feature and is a function.


Delicious77 [7]3 years ago
5 0

Answer:

yes it's a function

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Step-by-step explanation:

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The director of health services is concerned about a possible flu outbreak at her college.
Anna [14]
"Given that he is male" is an important phrase here. The "given" in any probability problem is often important. This tells us "only focus on the males" because we know 100% that whoever we picked, the person is a male. 

So we only focus on the "male" column. Use a highlighter to mark this column or cover up the other values if they are too distracting. There are 51 males total (bottom row) and 39 males had a flu shot (top row)

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3 years ago
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Explain how you could mentally find 8 x 45 by using the distributive property
dangina [55]
First, break up 45 into 40 and 5 then multipy 8(40) which equals 320 and multipy 8(5) which equals 40. Thrn add 320+40 to get the product 360.
Hope this helped

8x45
8(40)+8(5)
320+40
360
6 0
3 years ago
If u make 120.45 in 15 2/3 hours how long did u work if u made 40.15 ?
Novosadov [1.4K]

Answer:

about 5.22hrs

Step-by-step explanation:

cross multiply

<u>120.45</u>          <u>?</u>

15.67         40.15

120.45*40.15

=629.1505

629.1505/15.67

=5.2233333...

5 0
3 years ago
Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125
liq [111]

For the given equation;

(3x-5)^2=-125

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}

Now that we have expanded the left side of the equation, we would have;

\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}

ANSWER:

x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}

3 0
11 months ago
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