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Lelu [443]
2 years ago
5

2x+3y=9

Mathematics
2 answers:
Maslowich2 years ago
4 0
This was my answer for someone else question exactly like this :)

Radda [10]2 years ago
4 0
Answer: x=3, y=1

- multiply the second equation by -2; it becomes -2x-10y= -16
- add 2x+3y=9 and -2x-10y= -16
- we get -7y=-7
- solve for y by dividing both sides by -7
- we get y=1
- now that we have found y, we pick either original equation to plug it into to get the value of x
- if we use 2x+3y=9, we plug 1 in for y to get 2x+3(1)=9
- 3x1=3, so the equation is now 2x+3=9
- to eliminate the 3, we add -3 to both sides.
- after that, we are left with 2x=6
- by dividing both sides by 2, we are left with x=3
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laila [671]

Im 75% sure the answer is -3.

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Step-by-step explanation:

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8 0
3 years ago
Find the solution of the system of equations.<br><br> x-y=-3<br>-8x+y=45
mezya [45]

Answer:

x = 17, y = 28

Step-by-step explanation:

1. Isolate for x in "x - y = -3, -8":

x - y+y = -3, -8+y

x = -11 + y

2. Substitute "x = -11 + y" in for x in the second expression:

-11 + y + y = 45

3. Simplify:

-11 + 2y = 45

4. Isolate y:

-11+11 +2y = 45+11

2y = 56

\frac{2y}{2} = \frac{56}{2}

y = 28

5. Substitute the new y-value into the first equation:

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hope this helps!

5 0
1 year ago
16 - 2z-4/3 when z=18
Colt1911 [192]

Answer:

z= -3

Step-by-step explanation

5 0
3 years ago
Please answer this correctly without making mistakes
Monica [59]

Answer:

g=56

Step-by-step explanation:

In similar shapes, corresponding sides are always in the same ratio.

For example,

if the sides in triangle 1 were a and b, and triangle 2 had side lengths c and d, c and a had the same ratios, and b and d had the same ratios

and triangle 1 was similar to triangle 2, the ratio between the sides of the triangles would be

a/c, which is also equal to b/d

What that means is that in this situation, 8/5=g/35.

8/5=g/35

Cross multiply.

(8)*(35)=g*(5)

280=5g

g=56

4 0
3 years ago
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