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Lelu [443]
3 years ago
5

2x+3y=9

Mathematics
2 answers:
Maslowich3 years ago
4 0
This was my answer for someone else question exactly like this :)

Radda [10]3 years ago
4 0
Answer: x=3, y=1

- multiply the second equation by -2; it becomes -2x-10y= -16
- add 2x+3y=9 and -2x-10y= -16
- we get -7y=-7
- solve for y by dividing both sides by -7
- we get y=1
- now that we have found y, we pick either original equation to plug it into to get the value of x
- if we use 2x+3y=9, we plug 1 in for y to get 2x+3(1)=9
- 3x1=3, so the equation is now 2x+3=9
- to eliminate the 3, we add -3 to both sides.
- after that, we are left with 2x=6
- by dividing both sides by 2, we are left with x=3
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Veseljchak [2.6K]

Answer:

3.8$

Step-by-step explanation:

You have to figure out $/hours.

19/5= 3.8  $/hours

8 0
3 years ago
A mirror frame in the shape of an oval is shown below. The ends of the frame form semicircles: (5 points)
guapka [62]

Answer:

696.265 inches

Step-by-step explanation:

Radius = 27/2 = 13.5

2 semicircles + 2 lengths

(3.14 × 13.5²) + 2(62)

696.265 inches

4 0
3 years ago
Question in picture #21 only
krek1111 [17]
Number 21 is the first answer a.) 8
3 0
3 years ago
Read 2 more answers
Consider two vectors A and B A=14i and B= -4i+8j
DaniilM [7]
Assuming \mathbf a,\mathbf b\in\mathbb R^3, you have

\mathbf a\cdot\mathbf b=(14)(-4)+(0)(8)=-56

so

((\mathbf a\cdot\mathbf b)\,\mathbf i)\cdot\mathbf a=(-56\,\mathbf i)\cdot(14\,\mathbf i)=(-56)(14)=-784

Next,

\mathbf a+\mathbf b=(14\,\mathbf i)+(-4\,\mathbf i+8\,\mathbf j)=10\,\mathbf i+8\,\mathbf j

Then

(\mathbf a+\mathbf b)\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\10&8&0\\-4&8&0\end{vmatrix}=112\,\mathbf k

((\mathbf a+\mathbf b)\times\mathbf b)\times\mathbf k=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&112\\0&0&1\end{vmatrix}=\mathbf 0
4 0
3 years ago
What is the nth term rule of the linear sequence below? 15 , 7 , − 1 , − 9 , − 17 , . . .
Doss [256]

You can see that you're constantly subtracting 8 to get the next number. So, we have

a_1 = 15

a_2 = a_1-8

a_3 = a_2-8 = (a_1-8)-8=a_1-2\cdot 8

a_4=a_1-3\cdot 8

a_5=a_1-4\cdot 8

So, as you can see, to get the n-th term we must subtract (n-1) times 8 from the original number.

7 0
3 years ago
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