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lys-0071 [83]
3 years ago
15

Which of the following has a value of 84? A. 512 B. 4,096 C. 32 D. 83

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0
Answer is B. 4,096

I encountered this problem before. This is a trick question.
84 is not really the number 84. It is 8 raised to the 4th power.

So 8⁴ is equal to 4,096.

8 x 8 x 8 x 8 = 4,096

    8 x 8 =      64
  64 x 8 =    512
512 x 8 = 4,096




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Jay estimates that a basketball weights about .5 pounds. Shawna estimates that a basketball weights about.05. Whose estimate is
Natasha_Volkova [10]

Answer:

Jay's estimate is closer to the actual weight of the basketball

Step-by-step explanation:

The standard weight of an NBA basketball is 1.4 pounds.

Judging the accuracy of Jay's and Shawna's answer based on their percentage error when compared with the standard, we have that Jay's answer has a lower error as shown below

Error  = (Standard value - Estimated value)/ Standard Value ×100

Error in Jays answer = \frac{1.4 - 0.5}{1.4} × 100 = 64.28 %

Error in Shawna's answer = \frac{1.4 - 0.05}{1.4} × 100 = 96.42%

From this, It is obvious that Jay's answer has a lower percentage error when compared to the actual value.

8 0
3 years ago
Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

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Step-by-step explanation:

18-6=2+y

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