H=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
(the whole left side of the equation is divided by 2 i just cant do it on the computer)
Angle R= 36°
180-68-76=36°
Answer:
2
Step-by-step explanation:
Given g(x) = sin(x)-1/cos2(x), we are to find the limit if the function g(x) as g(x) tends to π/2
Substituting π/2 into the function
lim x-->π/2 sin(x)-1/cos 2(x)
= sin(π/2) - 1/cos(2)(π/2)
= 1 - 1/cosπ
= 1- 1/-1
= 1 -(-1)
= 1+1
= 2
Hence the limit of the function h(x) = sin(x)-1/cos2(x) as x--> π/2 is 2
I'll do part (a) to get you started.
The angle 'a' pairs up with the 123 degree angle as a corresponding angle pair. Due to the parallel lines, the corresponding angles are congruent. Therefore a = 123.
We also see that b = 123 as well since a = b (they are vertical angles).
Notice how angle c is adjacent to the 123 degree angle. These two angles form a straight line, so they must add to 180 degrees.
c+123 = 180
c = 180-123
c = 57
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To summarize, we have these three angles
a = 123
b = 123
c = 57
