If 6 newborn babies are randomly selected, how many different gender sequences are possible?
1 answer:
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Answer:
The function y = sec(x) shifted 3 units left and 7 units down .
Step-by-step explanation:
Given the function: y = sec(x)
- If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.
- If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.
The function comes from the base function y= sec(x).
Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.
Therefore, the transformation on the given function is shifted 3 units left and 7 units down
Answer:
see below
Step-by-step explanation:
The parent function is x^2 which is a parabola at vertex (0,0)
g(x) = ( x+3) ^2
y = f(x + C) C > 0 moves it left
So the parabola is shifted to the left 3 units
h(x) = -( x+3) ^2
y = −f(x)
Reflects it about x-axis
Means flip it about the x axis
