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3 years ago

If 6 newborn babies are randomly selected, how many different gender sequences are possible?

Mathematics

1 answer:

Citrus2011 [14]3 years ago

7 0

The answer that i got was 720 different sequence genders are possible if 6 new born babies are randomly selected

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In expanded form, in kilometers, how far is Jupiter from the Sun?

DIA [1.3K]

<span>740,679,835 km i hope this helps you
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3 years ago

Solve for x <br><br> -7(1-8x)=105

Sunny_sXe [5.5K]

-7 + 56x = 105
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56x = 112
x = 2

4 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago

Givien h(x) = -x- 5, find h(-6)

garik1379 [7]

Answer:

h(-6) = 1

Step-by-step explanation:

Hello!

Substitute -6 for x in the equation.

<h3>Evaluate</h3>

h(x) = -x - 5
h(-6) = -(-6) - 5
h(-6) = 6 - 5
h(-6) = 1

h(-6) is 1.

3 0

1 year ago

What do the following two equations represent? -3x-y = 3−3x−y=3minus, 3, x, minus, y, equals, 3 -3x-y = 3−3x−y=3

allochka39001 [22]

3 x minus y equals 3

4 0

3 years ago