Question

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Answer 1

Given:

The size of object = 4.0cm

Distance of the object = 25cm (-ve as it is in front

of mirrors)

focal length of concave mirror = 15cm (-ve) Distance of the image is given by

1/v+1/u = 1/f

1/v +1/-25=1/-15

1/v = 1/-15+1/25

= -10+6/150

=-4/150=v

v = -37.5

The size of the image is given by

h^1/h^0 =-v-/u

h^1 = -v- *h^0

=> -(-37.5)*4/25

=>-150/25

=> -6 Cm

Image will be 6cm high and it will be inverted.

( Negative sign indicates that the image is below

the principal axis.

Therefore, the size of the image is 6 cm.)