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3 years ago

A Storage box can hold 810 ft.³ of sugar if the box is 9 feet wide and 10 feet long how deep is it?

Mathematics

2 answers:

Anna35 [415]3 years ago

6 0

X-9 Feet long that would be correct answer

noname [10]3 years ago

4 0

The volume is 810 ft^3= 9*10 *x
810=90x
x=810/90
x=9 feet is the long

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Inverse of f(x) = x2 − 9

luda_lava [24]

To find the inverse of a function, replace every x in the equation with a y, and replace every y in the equation with an x:

$x = y^{2} - 9$

Add 9 to both sides:

$y^{2} = x + 9$

Square root both sides to get y by itself:

$y = \sqrt{x+9}$

This equation can be simplified by taking the square root of 9 out of the root:

$\sqrt{9} = 3$
$y = 3 + \sqrt{x}$

The inverse of this function is y = 3 + √x.

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3 years ago

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Luda [366]

Answer:

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3 years ago

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Nina [5.8K]

15 because it’s 3 times the actual amount

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3 years ago

26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics

hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

$\mu _d = \mu _{post} - \mu _{pre}$

Then the null hypotheses and alternative hypotheses will be

H₀: $\mu _d = 0$

Hₐ: $\mu _d > 0$

Then the test statistic will be

$\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5$

Then

$\rm S_d = 6.02$

The test statistic value is given by

$\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16$

Since this is a right-tailed test, so the critical value is given by

$\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353$

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that $\mu _d > 0$ that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

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2 years ago

Calculate the number of ways to form a set of three distinct items such that no two of the selected items are in the same row or

Eddi Din [679]

Answer:

1200

Explanation:

Order does not matter, if we said xyz order, it would still not make a difference if it was zyx or yzx hence we use the combination formula:

nCr = n! / r! * (n - r)!

where n= total number of items

r= number of items chosen at a time

Combinations are used when the order of events do not matter in calculating the outcome.

We calculate using the formula:

(30×20×12)÷3!=1200

There are therefore 1200 ways for the three distinct items to not be in same row or column

8 0

3 years ago