Given:
Bases of trapezoid : 11 meters and 14 meters
height of trapezoid : 10 meters
Area of trapezoid = (sum of bases / 2) height
A = (11m + 14m)/2 * 10m
A = 25m / 2 * 10m
A = 12.5m * 10m
A = 125m²
1. D. because the angels of KRC and CRH added together is 180 degrees. Which equals a straight line.
2. Answer is A . BHR is equal to NHD, so it is 8x. But we need to find x first.
The right angle in the picture is 8x + (9x +5)
90 =8x + 9x +5
90 = 17x + 5
85 = 17 x
5 = x.
X is 5 so 8x is 40.
3. B. The opposite angles are equal to each other. and the sum of two angles side by side equal 180.
6x - 82 = 3x +23
group like terms
6x - 3x = 23 + 82
3x = 105
x = 35.
Answer is B
4.B. a complement angle added together will get you 90.
90 - 41 = 49
Answer is B
3y+4y+6=20
(3y+4y)+(6)=20
(Combine Like Terms)
7y+6=20
7y+6=20
Subtract 6 from both sides.
7y + 6 − 6 = 20 − 6
7y = 14
Divide both sides by 7.
7y/7 = 14/7
y = 2
-23-(-113)
Subtract -113 from -23. This would also be the same as adding 113 to -23 because the two negative signs are equal to one positive sign.
Final Answer: 90
