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2 years ago

What is food...................................

Mathematics

2 answers:

Leona [35]2 years ago

7 0

Answer:

Any solid substance that can be consumed by living organisms, especially by eating , in order to sustain life is food.

Step-by-step explanation:

balu736 [363]2 years ago

3 0

Food is any substance consumed to provide nutritional support for an organism.

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My homework says rewrite each statement using symbols for example one says

timurjin [86]

Well the question says "rewrite each statement using symbols so I guess it means using symbols...

4 0

3 years ago

Read 2 more answers

See attached picture

yanalaym [24]

Answer:

$\frac{f(x+h)-f(x)}{h}$ $=2x + h$

Step-by-step explanation:

Given

$f(x)= x^2 + 2$

Required

Determine: $\frac{f(x+h)-f(x)}{h}$

First, we calculate f(x + h)

$f(x)= x^2 + 2$

$f(x+h) = (x+h)^2+2$

$f(x+h) = x^2+2xh+h^2+2$

So, we have:

$\frac{f(x+h)-f(x)}{h}$ $= \frac{x^2 + 2xh + h^2 + 2 - x^2 - 2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $= \frac{x^2 - x^2+ 2xh + h^2 + 2 - 2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $= \frac{2xh + h^2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $=2x + h$

8 0

2 years ago

Sue a tollbooth worker is paid $12.50 per hour between 8 Am and 4 pm. After 4 pm she is paid $14.25 per hour. If Sue works from

katrin2010 [14]

Answer:

She earns that day $103.5

Step-by-step explanation:

Lets explain how to solve the question

- She is paid $12.50 per hour between 8 am and 4 pm

- After 4 pm she is paid $14.25 per hour

- She works one particular day from 10 am to 6 pm

* Lets distribute her time of work into two part according to her

payment above

# 1st part from 10 am to 4 pm

∵ She is paid $12.50 per hour between 8 am to 4 pm

∵ She works from 10 am to 4 pm

- Calculate how many hours between 10 am and 4 pm

∵ am and pm not like terms in time, so change the time to 24-hours

∵ 4 pm in 24-hour time is 4 + 12 = 16

∴ She works form 10 to 16

∴ She works for 6 hours (16 - 10 = 6)

∴ She is paid = 12.50 × 6 = $75

# 2nd part after 4 pm to 6 pm

∵ She is paid $14.25 per hour after 4 pm

∵ She works from 4 pm to 6 pm

- Calculate how many hours between 4 pm and 6 pm

∵ Both times are pm

∴ She works for 2 hours (6 - 4 = 2)

∴ She is paid = 14.25 × 2 = $28.5

- Add the two answers of the 1st part and the 2nd part

∴ She earns = 75 + 28.5 = $103.5

* She earns that day $103.5

7 0

3 years ago

Read 2 more answers

The navigator on the ship uses a compass to draw a circle on a nautical chart to indicate the ship's position. The circle has a

Ilya [14]

Answer:

I think it's 12 my bad if it's wrong

4 0

2 years ago

For what values of x is log base 0.8 (x+4)>log base 0.4 (x+4)<br>Thank you!

Radda [10]

We are seeking the solution of the inequality:

$\displaystyle{ \log_{0.8}(x+4)\ \textgreater \ \log_{0.4}(x+4)$ .

We recall that a log function $f(x)=\log_b(x)$ is either increasing or decreasing:

i) it is increasing if b>1,

ii) it is decreasing if 0<b<1.

Consider the functions $\displaystyle{ \log_{0.8}(x)$ and $\displaystyle{ \log_{0.4}(x)$ .

The graphs of these functions both meet at x=1 (clearly), and after 1 they are both negative. So from 0 to 1 one of them is larger for all x, and from 1 to infinity the other is larger. (Being strictly decreasing, their graphs can only intersect once.)

We can check for a certain convenient point, for example x=0.8:

$\displaystyle{ \log_{0.8}(0.8)=1$ and

$\displaystyle{ \log_{0.4}(0.8)=\log_{0.4}(0.4\cdot 2)=\log_{0.4}(0.4)+\log_{0.4}(\cdot 2)=1+\log_{0.4}(2)$ .

Now, $\displaystyle{ \log_{0.4}(2)$ is negative since we already explained that for x>1 both functions were negative. This means that

$\displaystyle{ \log_{0.8}(0.8)\ \textgreater \ \log_{0.4}(0.8)$ , and since $0.8\in (0, 1)$ , then this is the interval where $\displaystyle{ \log_{0.8}(x)\ \textgreater \ \log_{0.4}(x)$ .

So, now considering the functions $\displaystyle{ \log_{0.8}(x+4)$ and $\displaystyle{ \log_{0.4}(x+4)$ , we see that

x+4 must be in the interval (0,1), so we solve:

0<x+4<1, which yields -4<x<-3 after we subtract by 4.

Answer: (-4, -3). Attached is the graph generated using Desmos.

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2 years ago