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Mazyrski [523]
2 years ago
10

If its length is 4x - 3 meters and its width is 2x + 6meters , what is the actual width of the rectangle?

Mathematics
1 answer:
torisob [31]2 years ago
6 0

Answer:

p

=

2

(

4

x

+

3

)

+

2

(

2

x

−

6

)

or simplified  

p

=

12

x

−

9

Explanation:

By definition the perimeter of an object is the length of all its sides.

Also by definition, for a rectangle the 2 sides of the width are equal and the 2 sides of the length are equal.

Therefore the equation for the perimeter of a rectangle can be written as:

p

=

2

⋅

l

+

2

⋅

w

where  

p

is the perimeter,  

l

is the length and  

w

is the width.

Substituting what was given about the length and width gives the equation:

p

=

2

(

4

x

+

3

)

+

2

(

2

x

−

6

)

Simplifying this equation gives:

p

=

8

x

+

3

+

4

x

−

12

p

=

8

x

+

4

x

+

3

−

12

p

=

12

x

−

9

Step-by-step explanation:

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Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur
Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle

for 0\le u\le7 and 0\le v\le\frac{2\pi}3, and a normal vector to this surface is

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle

with norm

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}

So the integral of f(x,y,z)=x^2+y^2+z^2 is

\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}

6 0
2 years ago
How do yo work out 9.1 divided by 3575
EastWind [94]
9.1/3575
use long division like this
         _<u>0.</u>_________
3575|91.000000

we find how many of 3575 fit into the 91
it's too big so we go farther
how many 3575 go into 910
too big so we go farther
how many 3575 go into 9100
the answer is 2 so put that in the correct place and mulitply that and put that in the correct place. then we subtract

         _<u>0.</u><u>02</u>_________
3575|91.000000
        -<u>71.50</u>
         19.50
bring down the next number
find how many go into 19.500
the answe ris 5


         _<u>0.</u><u>02</u><u>5</u>_________
3575|91.000000
        -<u>71.50</u>
         19.500
        -<u>17.875</u>
           1.625
          
bring down he next zero ( I fast forward and skip steps for convinience)

                      __
         _<u>0.</u><u>02</u><u>5</u><u>455</u>_________
3575|91.000000
        -<u>71.50</u>
         19.500
        -<u>17.875</u>
           1.6250
          -<u>1.4300</u>
             .19500
            -<u>.17875
</u>                16250
               -14300
and so on untill infinity so the answe ris 0.0254555555555555 (enless fives)
8 0
3 years ago
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