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d1i1m1o1n [39]
3 years ago
15

Mayra's monthly salary is $4,540 plus she earns an 8% commission on her sales each month. Mayra's sales for January were $30,000

. What were her total earnings for january?
Mathematics
1 answer:
lesantik [10]3 years ago
7 0
Work out 8% of 30000

10% of 30000 is 3000

1% of 30000 is 300
2% of 30000 is 300x2=600

Therefore 10%-2%= 3000-600=2400

It therefore follows that Mayra earned 4540 + 2400 = 6940 for January

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Which expression is the factored form of x2 – 7x 10? (x 3)(x 4) (x – 3)(x – 4) (x – 2)(x – 5) (x 2)(x 5)
alexandr402 [8]

The expression x^2 -7x + 10 can be written in factored form as given by Option C: (x-2)(x-5)

<h3>How to find the factors of a quadratic expression?</h3>

If the given quadratic expression is of the form ax^2 + bx + c

then its factored form is obtained by two numbers alpha( α ) and beta( β) such that:

b = \alpha + \beta \\ ac =\alpha \times \beta

Then writing b in terms of alpha and beta would help us getting common factors out.

Sometimes, it is not possible to find factors easily, so using the quadratic equation formula can help out without any trial and error.

For this case, we're provided the expression:

x^2 -7x + 10

We can write 10 as multiple of -5 and -2 and

we can write -7 as sum of -5 and -2. Thus, we get:

x^2 -7x + 10 = x^2 -5x - 2x + 10 = x(x-5+ -2(x-5) = (x-2)(x-5)

Thus, the expression x^2 -7x + 10 can be written in factored form as given by Option C: (x-2)(x-5)

Learn more about factorization of quadratic expression here:

brainly.com/question/26675692

4 0
3 years ago
a bowl of candies contains the following makeup of colors: 4 red, 2 yellow, 5 green, and 1 purple. taina is selecting a candy at
Ivanshal [37]

<u>Candies</u>

4 red

2 yellow

5 green

1 purple

- Taina doesn't like red candies.

4/4+2+5+1 = 4/12

4/12 is the probability Taina <em>will</em> get a red candy, but we're looking for the opposite.

12/12 - 4/12 = 8/12 = 2/3

The probability Taina will not select a red candy is 2/3.

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3 years ago
Write the equation of the cosecant function with domain
zloy xaker [14]

Answer:

wait can u put it in a way that i can understand it pls and thank you

Step-by-step explanation:

4 0
3 years ago
Ricardo and Tammy practice putting golf balls. Ricardo makes 47% of his putts and Tammy makes 51% of her putts. Suppose that Ric
yaroslaw [1]

Answer:

0.3821 = 38.21% probability that Ricardo makes a higher proportion of putts than Tammy.

Step-by-step explanation:

To solve this question, we need to understand the normal distribution, the central limit theorem, and subtraction of normal variables.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction of normal variables:

When we subtract normal variables, the mean of the subtraction will be the subtraction of the means, while the standard deviation will be the square root of the sum of the variances.

Ricardo makes 47% of his putts, and attempts 25 putts.

By the Central Limit Theorem, we have that:

\mu_R = 0.47, s_R = \sqrt{\frac{0.47*0.53}{25}} = 0.0998

Tammy makes 51% of her putts, and attempts 30 putts.

By the Central Limit Theorem, we have that:

\mu_T = 0.51, s_T = \sqrt{\frac{0.51*0.49}{30}} = 0.0913

What is the probability that Ricardo makes a higher proportion of putts than Tammy?

This is the probability that the subtraction of R by T is larger than 0. The mean and standard deviation of this distribution are, respectively:

\mu = \mu_R - \mu_T = 0.47 - 0.51 = -0.04

s = \sqrt{s_R^2 + s_T^2} = \sqrt{0.0998^2 + 0.0913^2} = 0.1353

This probability is 1 subtracted by the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0 - (-0.04)}{0.1353}

Z = 0.3

Z = 0.3 has a pvalue of 0.6179

1 - 0.6179 = 0.3821

0.3821 = 38.21% probability that Ricardo makes a higher proportion of putts than Tammy.

6 0
3 years ago
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